Answer:
160:340
Step-by-step explanation:
The hours between 2:00pm and 4:00pm is 2 hours. If originally 350 freshman and 200 sophomores are at the carnival, and 20 freshman leave every hour, we can determine how many freshman left in 2 hours:
and if 35 sophomores arrive every half our, we know that for every two hours there is 4 half hours, therefore:
The amount of freshman at 4:00pm:
and the amount of sophomores:
the ratio is 160:340
Standard form is y=mx+b
y=9x+4
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
The equation has 1 solution