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mylen [45]
3 years ago
6

X 1 2 3 4 5 Y 1 3 5 7 9

Mathematics
1 answer:
mina [271]3 years ago
6 0

Option D:

y = 2x – 1; y is twice x minus 1.

Solution:

Option A: y = 2x; y is double x

substitute x values in y = 2x, we get

For x = 1, y = 2(1) = 2

so, y = 2x is false.

Option B: y = 3x; y is triple x

substitute x values in y = 3x, we get

For x = 1, y = 3(1) = 3

so, y = 3x is false.

Option C: y = 2x + 1; y is twice x plus 1.

substitute x values in y = 2x + 1, we get

For x = 1, y = 2(1) + 1 = 3

so, y = 2x + 1 is false.

Option D: y = 2x – 1; y is twice x minus 1.

substitute x values in y = 3x, we get

For x = 1, y = 2(1) – 1 = 1

For x = 2, y = 2(2) – 1 = 3

For x = 3, y = 2(3) – 1 = 5

For x = 4, y = 2(4) – 1 = 7

For x = 5, y = 2(5) – 1 = 9

so, y = 2x – 1 is true.

Hence the expression for the table is y = 2x – 1;  y is twice x minus 1.

Each value of y is double that of corresponding value of x, minus 1.

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Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

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The margin of error is:

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Sample size needed

At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.09}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}

n = 118.6

Rounding up

We need a sample size of least 119

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