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Montano1993 [528]
4 years ago
11

8 meters increased by 25% find new amount

Mathematics
2 answers:
Vika [28.1K]4 years ago
8 0
[ 8+0.25(8)] m = 10m hope this is the right answer .
kifflom [539]4 years ago
6 0
<h3>Answer: 10 meters</h3>

=====================================

Explanation:

Take 25% of 8 to get 0.25*8 = 2

The length increased by 2 meters, meaning that the final length is

8+2 = 10

-----

Alternatively, multiply 1.25 by 8 to get 1.25*8 = 10

The 1.25 multiplier refers to 100% + 25% = 1.00 + 0.25 = 1.25

So we start with 100% (the original value 8) and then add on 25% of that (2) to get the final answer 10

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Please help asap math watch!!
babymother [125]

Answer:

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Step-by-step explanation:

It is easier to work the exterior angle first.

<h3>b)</h3>

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  360°/12 = 30° . . . the measure of one exterior angle

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<h3>a)</h3>

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3 years ago
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lukranit [14]
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7 0
3 years ago
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Galina-37 [17]
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3 0
3 years ago
Prove De Morgan's law by showing that each side is a subset of the other side by considering x ∈ A⎯⎯⎯ A ¯ ∩ B⎯⎯⎯ B ¯ .
adelina 88 [10]

Solution :

We have to prove that $\overline{A \cup B} = \overline{A} \cap \overline{B}$   (De-Morgan's law)

Let  $x \in \bar{A} \cap \bar{B}, $ then $x \in \bar{A}$ and $x \in \bar{B} $

and so $x \notin \bar{A}$ and $x \notin \bar{B} $.

Thus, $x \notin A \cup B$ and so $x \in \overline{A \cup B}$

Hence, $\bar{A} \cap \bar{B} \subset \overline{A \cup B}$   .........(1)

Now we will show that $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$

Let $x \in \overline{A \cup B}$ ⇒ $x \notin A \cup B$

Thus x is present neither in the set A nor in the set B, so by definition of the union of the sets, by definition of the complement.

$x \in \overline{A}$ and  $x \in \overline{B}$

Therefore, $x \in \overline{A} \cap \overline{B}$ and we have $\overline{A \cup B} \subset \overline{A} \cap \overline{B}$  .............(2)

From (1) and (2),

$\overline{A \cup B} = \overline{A} \cap \overline{B}$

Hence proved.

3 0
3 years ago
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