If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l
now

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum
notice the

so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0
so.. check the critical points on the other
Perimeter: 9+9+8+8= 34 ft.
Area: 9*8= 72 ft²
Answer:
160
Step-by-step explanation:
The measure of an arc is always twice the degree of the corresponding angle inside the circle. For example, the measure of arc DC is just double the measure of angle DOC; angle DOC is 44 degrees, so arc DC must be 88 degrees.
Angle COB is 80 degrees, so arc CB is 160 degrees.
Answer:
I think it can be 12 and -6
Step-by-step explanation:
The sum has to be equal to 6
12+ -6= 6
Also, the two integers have opposite signs as asked in the question
I think like 5 to 6 hours in a jet