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Anit [1.1K]
3 years ago
14

How can i write all the names that apply √36

Mathematics
1 answer:
mihalych1998 [28]3 years ago
8 0
One of the answers is 6 
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You can sand frac{4}{9}
Reptile [31]

Answer:

Step-by-step explanation:

2 and 38/45 square yards can be sanded in 3.2 hours.

Step-by-step explanation:

1/2 of an hour is 30 minutes. so 4/9 for every 30 minutes. 1 hour is 8/9. So 3 2/10 would be 3 hours =24/9=2 6/9 and 2/10 would be ( if 5/10 is 30 minutes then 2/10 is 12 minutes.) 8/9 x 1/5 = 8/45. (24 x 5 = 120) 120/45 + 8/45 is 128/45 = 2 38/45

7 0
3 years ago
You invest 4,100 in an account that pays an interest rate of 7.25% ,compounded continuously. Calculate the balance of your accou
levacccp [35]
\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount}
\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$4100\\
r=rate\to 7.25\%\to \frac{7.25}{100}\to &0.0725\\
t=years\to &8
\end{cases}
\\\\\\
A=4100e^{0.0725\cdot 8}\implies A=4100e^{0.58}\implies A\approx 7322.757566075
8 0
3 years ago
Sibal started with $500 in a bank account that does not earn interest. In the middle of every month, she withdraws 15 of the acc
Otrada [13]
After every month's withdrawals, 4/5 of the original amount at the start of the month will remain. The amount at the start of every month will change. Thus:
an = 4/5 (an-1) ; where a1 = 500.
4 0
3 years ago
You received partial credit in th
Blababa [14]

Answer:

Expected value would be $ 0.896

Step-by-step explanation:

Given,

The price of the lottery ticket = $44800000,

Also, the probability of winning the grand prize = .000000020,

Thus, the expected value of the lottery ticket = value of the lottery ticket × probability of getting the lottery ticket

= 44800000 × .000000020

= $0.896

Note : value of lottery ticket = prize amount - cost of each ticket,

Here the cost price of a ticket is not given,

That's why we did not consider it.

5 0
2 years ago
Suppose that contamination particle size (in micrometers) canbe modeled as
asambeis [7]

Answer:

c) 2

d) 0.96

Step-by-step explanation:

We are given the following in the question:

f(x) = 2x^{-3}, x > 1\\~~~~~~~= 0, x \leq 1

a) probability density function.

\displaystyle\int^{\infty}_{\infty}f(x) dx = 1\\\\\displaystyle\int^{\infty}_{-\infty}2x^{-3}dx = 1\\\\\displaystyle\int^{\infty}_{1}2x^{-3}dx\\\\\Rightarrow \big[-x^{-2}\big]^{\infty}_1\\\\\Rightarrow -(0-1) = 1

Thus, it is a probability density function.

b) cumulative distribution function.

P(X

c) mean of the distribution

\mu = \displaystyle\int^{\infty}_{-\infty}xf(x) dx\\\\\mu = \int^{\infty}_12x^{-2}dx\\\\\mu = (-\frac{2}{x})^{\infty}_{1}\\\\\mu = 2

d) probability that the size of random particle will be less than 5 micrometers

P(X

4 0
2 years ago
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