A/2-b/3=1 solve for a, add b/3 to both sides
a/2=1+b/3 which is equal to
a/2=(3+b)/3 multiply both sides by 2
a=(6+2b)/3 now you can substitute this into 2a+3b giving you:
2(6+2b)/3 + 3b which is equal to
(12+4b+9b)/3
(13b+12)/3
Answer:
<em>4.52secs</em>
Step-by-step explanation:
Given the height of a falling object expressed as;
d=3t+5t^2
If the object travel 84 feet, we are to find the time t it takes to travel. On substituting;
84 = 3t+5t^2
3t+5t^2 - 84 = 0
t = -5±√25-4(3)(-84)/2(3)
t = -5±√25+1008/6
t = -5±32.14/6
t = -5+32.14/6
t = 27.14/6
<em>t = 4.52 secs</em>
<em>Hence it will take 4.52secs for the object to travel 84feet</em>
4z>-60
divideby 4
z>-15
x+19 <=-5
subtract 19 from each side
x<= -24
