All categories

3 years ago

How many degrees are there in a one quarter term?

1 answer:

3 0

90. This is because a whole term is 360 degrees. So divide it by 4 to get the answer of a quarter term. Same goes for half term, dived 360 by 2 to get 180 degrees.

You might be interested in

Consider the quadratic function:

sdas [7]

Answer:

Step-by-step explanation:

I'm not sure how you are finding this in class, but the easiest way by far is to use the expressions for h and k:

$h=\frac{-b}{2a}$ and

$k=c-\frac{b^2}{4a}$

(Just a fun fact: Those expressions come from the quadratic formula that help us to factor a quadratic equation.)

Filling in for h:

$h=\frac{-(-8)}{2(1)}$ simplifies to

$h = \frac{8}{2}=4$

Filling in for k:

$k=-9-\frac{(-8)^2}{4(1)}$ which simplifies a bit to

$k=-9-\frac{64}{4}$ which simplifies a bit more to

$k=-9-16=-25$

The vertex, then, is (4, -25).

You would also find this if you completed the square. But again, I'm not sure how you're solving for the vertex in class.

8 0

3 years ago

What is the equation for the line that passes through the point (-7,-7) and has a slope of 1?

sladkih [1.3K]

Answer:

Step-by-step explanation:

4 0

3 years ago

Need the answer, anyone know?

GREYUIT [131]

I think it's A, but I'm not sure

4 0

4 years ago

Is this a reduction or enlargement?

Nesterboy [21]

Enlargement i think so

6 0

3 years ago

If discriminant (b^2 -4ac>0) how many real solutions

MaRussiya [10]

Answer:

If Discriminant, $b^{2} -4ac >0$

Then it has Two Real Solutions.

Step-by-step explanation:

To Find:

If discriminant (b^2 -4ac>0) how many real solutions

Solution:

Consider a Quadratic Equation in General Form as

$ax^{2} +bx+c=0$

then,

$b^{2} -4ac$ is called as Discriminant.

So,

If Discriminant, $b^{2} -4ac >0$

Then it has Two Real Solutions.

If Discriminant, $b^{2} -4ac < 0$

Then it has Two Imaginary Solutions.

If Discriminant, $b^{2} -4ac=0$

Then it has Two Equal and Real Solutions.

4 0

3 years ago