Answer:
(8x2−4x−8)(2x+3x+2)
=(8x2+−4x+−8)(2x+3x+2)
=(8x2)(2x)+(8x2)(3x)+(8x2)(2)+(−4x)(2x)+(−4x)(3x)+(−4x)(2)+(−8)(2x)+(−8)(3x)+(−8)(2)
=16x3+24x3+16x2−8x2−12x2−8x−16x−24x−16
=40x3−4x2−48x−16
Step-by-step explanation:
It is x-2/6 and if it is not there than ad f and put x-2/6
You have to use sin/cos/tan values
Answer:
D
Step-by-step explanation:
