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Lynna [10]
3 years ago
11

If f(x) = 1/3x^2 + 5, find f(-9). A. 248 B. -22 C. 11 D. 32

Mathematics
2 answers:
melamori03 [73]3 years ago
7 0

Answer:

D. 32

Step-by-step explanation:

For this problem, we simply plug -9 in for x in f(x):

f(x)=\frac{1}{3} x^2+5  ⇒  f(9)=\frac{1}{3} *(9^2)+5=\frac{1}{3} *81+5=27+5=32

Thus, the answer is D. 32.

Hope this helps!

anygoal [31]3 years ago
3 0

Answer:

D. 32

Step-by-step explanation:

f(-9) = ⅓(-9)² + 5

⅓(81) + 5

27 + 5

32

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Graph f(x) =-2x^+16x-30 by factoring to find the solutions, then find the coordinates of the vertex, and the axis of symmetry. I
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Answer:

<em>Observe attached image</em>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

<em>Axis of symmetry:</em>

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Step-by-step explanation:

<u>First factorize the function</u>

f (x) = -2x ^ 2 + 16x-30

<em>Take -2 as a common factor.</em>

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<em>Now factor the expression x ^ 2 -8x +15</em>

You must find two numbers that when you add them, obtain the result -8 and multiplying those numbers results in 15.

These numbers are -5 and -3

Then we can factor the expression in the following way:

f (x) = -2(x-5)(x-3)

<em><u>The quadratic function cuts the x-axis at </u></em><em>x = 3 and at x = 5.</em>

Now we find the coordinates of the vertex.

For a function of the form ax ^ 2 + bx + c the x coordinate of its vertex is:

x = \frac{-b}{2a}

In the function f (x) = -2x ^ 2 + 16x-30

a = -2\\b = 16\\c = 30

<u>Then the vertice is:</u>

x = \frac{-16}{2(-2)}\\\\x = 4

The y coordinate of the symmetry axis is

y = f (4) = -2 (4) ^ 2 +16 (4) -30\\\\y = 2

The axis of symmetry is a vertical line that cuts the parabola in two equal halves. This axis of symmetry always passes through the vertex.

<u>Then the axis of symmetry is the line</u>

x = 4

<u>The solutions and the vertice written as ordered pairs are:</u>

<em>Function zeros:</em>

(3, 0), (5, 0)

<em>Vertex:</em>

(4, 2)

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