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jolli1 [7]
3 years ago
6

I need help figuring out how to factor

mula1" title="3 {x}^{2} - 11x - 4" alt="3 {x}^{2} - 11x - 4" align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
Norma-Jean [14]3 years ago
7 0

Answer:

Step-by-step explanation:

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Anettt [7]
<h3>Factor</h3><h3>√x²+5x+3+2x²+10x-15=0</h3><h3>√x²+2x²+5x+10x+3-15=0</h3><h3>√3x²+15x-12=0</h3><h3>√3x²+(3(5x)+3×-4=0</h3><h3>√3(x²+5x)+3×-4=0</h3><h3>√3(x²+5x-4)=0</h3><h3> </h3>

please mark this answer as brainlist

8 0
3 years ago
if rhombus ABCD were reflected across the x axis to create rhombus A'B'C'D', what would the measure of angle D' be?​
Mrac [35]

Answer:

D.64

Step-by-step explanation:

A linear line equals up to 180

A+D=180

Substitute 116 for A

116+D=180

Subtract 116 from both sides

D=64

A reflection across the x-axis won't change the measure of an angle

The answer is 64.

8 0
3 years ago
How do you solve this <br> (-4) + (+6)
Keith_Richards [23]

Answer:

2

Step-by-step explanation:

-4+6=

6-4=

2

4 0
3 years ago
Read 2 more answers
An art project has an area of 63.6 square inches. What is the width, in inches, of the project?
Flura [38]

Answer:

The width of the art projects of area 63.6 square inches is 7.97 inches .

Step-by-step explanation:

Given as :

The area of the square art project = 63.6 square inches

Since The shape of the art project is square

So, The Area of square = A = side × side = side²

Now, let the measure of the width of art project = w inches

I.e side = w inches

or ,  A  = side²

Or , A = w²

Or, 63.6 = w²

So, w = \sqrt{63.6}

I.e w = 7.97 inches

So, the width of the projects = w = 7.97 inches

Hence The width of the art projects of area 63.6 square inches is 7.97 inches . Answer

4 0
4 years ago
Plz help due tonight
Wittaler [7]

Answer:

4x + 8 = 2x + 3 + 51 \\ 4x - 2x = 54 - 8 = 46 \\ 2x = 46 \\ x = 46 \div 2 = 23 \\ 2x + 3 = 2 \times 23 + 3 = 49 \\ 51 \\ 80

enjoy it

5 0
3 years ago
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