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Leviafan [203]
4 years ago
10

The diagram below shows the contents of a jar from which you select marbles at random.

Mathematics
1 answer:
Natalka [10]4 years ago
3 0
A.
\frac{4}{13}  \times  \frac{8}{13} =  \frac{32}{169}
b.
\frac{4}{13} \times  \frac{8}{12} =  \frac{32}{156}  =    \frac{8}{39}
c. no because on a you replace the marble and the denometers are the same and on b you put it aside which decreases the denometer by one
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Learning Task 1 4/625 11. 796 A. Simplify the radical expressions 1. V63 6. V24 2. 48 7. 781 3. 775 8. V128 4. 99 9. 340 5. 92 1
kompoz [17]

Question:

Simplify the radical expressions

1.\ \sqrt{63     2.\ \sqrt{48    3.\ \sqrt{75      4.\ \sqrt{99      5.\ \sqrt{92

6.\ \sqrt[3]{24}      7.\ \sqrt[3]{81}      8.\ \sqrt{128}     9.\sqrt[3]{40}     10.\ \sqrt[3]{135}

Answer:

\sqrt{63}= 3 \sqrt7

\sqrt{48} = 4\sqrt{3}

\sqrt{75} = 5\sqrt{3}

\sqrt{99} = 3 \sqrt{11

\sqrt{92} = 2\sqrt{23

\sqrt[3]{24} = 2 \sqrt[3]{3}

\sqrt[3]{81} =3\sqrt[3]{3}

\sqrt{128} = 8 \sqrt{2}

\sqrt[3]{40} = 2 \sqrt[3]{5}

\sqrt[3]{135} =3\sqrt[3]{5}

Step-by-step explanation:

1.\ \sqrt{63    

Express 63 as 9 * 7

\sqrt{63}= \sqrt{9 * 7

Split:

\sqrt{63}= \sqrt{9} * \sqrt7

\sqrt{63}= 3 * \sqrt7

\sqrt{63}= 3 \sqrt7

2.\ \sqrt{48    

Express 48 as 16 * 3

\sqrt{48} = \sqrt{16*3}

Split

\sqrt{48} = \sqrt{16}*\sqrt{3}

\sqrt{48} = 4*\sqrt{3}

\sqrt{48} = 4\sqrt{3}

3.\ \sqrt{75    

Express 75 as 25 * 3

\sqrt{75} = \sqrt{25*3}

Split

\sqrt{75} = \sqrt{25}*\sqrt{3}

\sqrt{75} = 5\sqrt{3}

4.\ \sqrt{99  

Express 99 as 9 * 11

\sqrt{99} = \sqrt{9} * \sqrt{11}

Split

\sqrt{99} = 3 \sqrt{11

5.\ \sqrt{92

Express 92 as 4 * 23

\sqrt{92} = \sqrt{4} * \sqrt{23

\sqrt{92} = 2* \sqrt{23

\sqrt{92} = 2\sqrt{23

6.\ \sqrt[3]{24}    

Express 24 as 8 * 3

\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}

Express 8 as 2^3

\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}

\sqrt[3]{24} = 2 \sqrt[3]{3}

7.\ \sqrt[3]{81}

Express 81 as 27 * 3

\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}

Express 27 as 3^3

\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}

\sqrt[3]{81} =3\sqrt[3]{3}

8.\ \sqrt{128}    

Express 128 as 64 * 2

\sqrt{128} = \sqrt{64} * \sqrt{2}

\sqrt{128} = 8 \sqrt{2}

9.\sqrt[3]{40}

Express 40 as 8 * 5

\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}

\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}

\sqrt[3]{40} = 2 \sqrt[3]{5}

10.\ \sqrt[3]{135}

Express 135 as 27 * 5

\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}

Express 27 as 3^3

\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}

\sqrt[3]{135} =3\sqrt[3]{5}

4 0
3 years ago
The distance in miles from Mercury to the Sun in scientific notation is 3.6 × 10
natka813 [3]

Answer:

wouldnt it be 4.2 ?

Step-by-step explanation:

7 0
3 years ago
What is the slope of the line passing through -7,-2 and 4,1
Vladimir [108]
The slope is for that would be 3/11
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Find the length of the line joining the points A(-2,10) and B(-8,2)
Vesnalui [34]

Length of the line

= \sqrt{((-2)-(-8))^{2}+(10-2)^{2}  }

= \sqrt{36+64}

=\sqrt{100}

= 10

6 0
2 years ago
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