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stepladder [879]

2 years ago

5

What 3342xdx4 i need to know in 20 sec

1 answer:

mixas84 [53]2 years ago

5 0

Answer:

13368d

Step-by-step explanation:

3342 x d x 4

= 13368 x d

= 13368d

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Given the following formula, with A = 27 and t = 3, solve for r. <br> A=p(1+rt)

Nookie1986 [14]

Answer:

<h2>A. $r=\frac{27-p}{3p}$ </h2>

Step-by-step explanation:

The given formula is

$A=p(1+rt)$

Where $A=27$ and $t=3$

To solve for $r$ , first we need to move $p$

$\frac{A}{p}=1+rt$

Then, we move the term 1

$\frac{A}{p}-1=rt$

Finally, we move the factor $t$

$\frac{\frac{A}{p}-1 }{t} =r$

Replacing given values, we have

$\frac{\frac{27}{p}-1 }{3} =r\\r=\frac{\frac{27-p}{p} }{3} \\r=\frac{27-p}{3p}$

Thereofre, the right answer is A.

7 0

2 years ago

Karen karlin bought some large frames for $15 each and some small frames for $8 each at a closeout sale. if she bought 22 frames

BaLLatris [955]

small frames ($8): s

large frames ($15): L

Cost: 8s + 15L = 239 ⇒ 1(8s + 15L = 239) ⇒ 8s + 15L = 239

Quantity: s + L = 22 ⇒ -8( s + L = 22) ⇒ <u> -8s -8 L = -176 </u>

7L = 63

L = 9

Quantity: s + L = 22 ⇒ s + (9) = 22 ⇒ s = 13

Answer: 13 small frames, 9 Large frames

7 0

3 years ago

Read 2 more answers

Suppose your school cost for this term were $7600 and financial aid covered 3/4 of that amount

netineya [11]

Financial aid would cover 5,700 and you would need to pay 1,900

5 0

2 years ago

Find the vector that has the same direction as 3, 2, −6 but has length 2.

Nata [24]

Answer:

The vector is $\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)$ .

Step-by-step explanation:

We can determine the equivalent vector ( $\vec r$ ), dimensionless, by means of the following formula:

$\vec r = \frac{\vec u}{\|\vec u\|} \cdot \|\vec r\|$ (1)

Where:

$\vec u$ - Original vector, dimensionless.

$\|\vec u\|$ - Norm of the original vector, dimensionless.

$\|\vec r\|$ - Norm of the new vector, dimensionless.

The norm of the original vector is determined by the following definition:

$\|\vec u\| = \sqrt{\vec u\,\bullet \,\vec u}$ (2)

If we know that $\vec u = (3, 2, -6)$ , then the norm of the original vector is:

$\|\vec u\| = \sqrt{(3)\cdot (3)+(2)\cdot (2)+(-6)\cdot (-6)}$

$\|\vec u\| = 7$

If we know that $\|\vec r\| = 2$ , then the new vector is:

$\vec r = \frac{2}{7}\cdot (3,2,-6)$

$\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)$

The vector is $\vec r = \left(\frac{6}{7},\frac{4}{7},-\frac{12}{7}\right)$ .

7 0

2 years ago

Will give brainlist if correct.

dsp73

Answer: $\frac{1}{16}$

Step-by-step explanation:

1. Original Equation: $4^4(4^-^7)(4)$

2.Simplify: $4^4(4^-^7)(4) ----> 4^4* 4^-^7 * 4\\$

3.Apply exponent rule: $4^4^-^7^+^1$

4. Simplify: $4^-^2\\$

5.Apply exponent rule: $\frac{1}{4^2}$

6.Simplify: $\frac{1}{16}$

7 0

2 years ago