1
2
3
6
I hope this helps I'm not exact sure
Solve for a over the real numbers:
a^2/3 - 1/a = a^2/6
Bring a^2/3 - 1/a together using the common denominator 3 a:
(a^3 - 3)/(3 a) = a^2/6
Cross multiply:
6 (a^3 - 3) = 3 a^3
Expand out terms of the left hand side:
6 a^3 - 18 = 3 a^3
Subtract 3 a^3 - 18 from both sides:
3 a^3 = 18
Divide both sides by 3:
a^3 = 6
Take cube roots of both sides:
Answer: a = 6^(1/3)
Hey!
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Solution:
~Isolate the 4
√x - 10 = 4
~Square both sides
√x - 10² = 4²
~Simplify
x - 10 = 16
~Add 16 to both sides
x - 10 + 10 = 16 + 10
~Simplify
x = 26
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Answer:
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Hope This Helped! Good Luck!
You have to change the fractions into improper fractions and then change the denominators so they are equal
Answer:
x = 2.6
Step-by-step explanation:
