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just olya [345]
3 years ago
9

Find the product and express it in scientific notation.

Mathematics
2 answers:
rodikova [14]3 years ago
8 0
The answer is b because you multiply 2.635 times 10 then subtract it by 6
Tresset [83]3 years ago
4 0

Answer:

b

Step-by-step explanation:

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PLEASE HELP
lukranit [14]

Answer:

Step-by-step explanation:

l = 34 cm

height = 30 cm

radius = 16 cm

surface area of cone = πr (l +r)

=3.14 *16 (34 + 16)

=50.24*50

=2512 cm^2

volume of a cone = \frac{1}{3}πr^2h

=\frac{1}{3}*3.14*16^2 *30

=1.0466*256*30

=8037.888

=8037.89 cm^3

3 0
3 years ago
HELP ASAP PLLLLLLLLLLS!
PolarNik [594]

Answer:

uummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Step-by-step explanation:

8 0
3 years ago
Determine the domain of the function f(x)=sqrt of x+3/(x+8)(x-2)
Karo-lina-s [1.5K]
Unclear.  Did you mean


<span>f(x)= [sqrt of x+3]
       --------------------
          (x+8)

or did you mean
                               3
</span><span>f(x)= [sqrt of x] + ----------
                              x+8


I will focus on the first possibility.  The domain of sqrt(x+3) is [-3,infinity).
The domain of    x+3
                          ------- is   "x is not equal to -8."
                            x+8

Then the overall domain would be simply [-3, infinity).
</span>
7 0
3 years ago
Write the Taylor Series for f(x) = sin(x)center
tangare [24]

Answer:

Taylor series of sin(x) centered at x = 0.

Step-by-step explanation:

Taylor series expansion:

\sum_{n=0}^N f^n(a)\displaystyle\frac{(x-a)^n}{n!}

Here, f(x) = sin (x) and a = 0

f(x) = \sin x, f(0) = 0\\f'(x) = \cos x, f'(0) = 1\\f''(x) = -\sin x, f''(0) = 0\\f'''(x) = -\cos x, f'''(0) = -1\\f^4(x) = \sin x, f^4(0) = 0\\f^5(x) = \cos x, f^5(0) = 0

Putting all the values and expanding, we get,

f(x) = f(a) + \displaystyle\frac{f'(a)(x-a)}{1!} + \displaystyle\frac{f''(a)(x-a)^2}{2!} + \displaystyle\frac{f'''(a)(x-a)^3}{3!} + \displaystyle\frac{f^4(a)(x-a)^4}{4!} + \displaystyle\frac{f^5(a)(x-a)^5}{5!} + ...\\\\= \sin 0 + \displaystyle\frac{x}{1!} +  \displaystyle\frac{(0)x^2}{2!} + \displaystyle\frac{(-1)x^3}{3!} + \displaystyle\frac{(0)x^4}{4!} + \displaystyle\frac{(1)x^5}{5!} + ...

Solving, we get

\sin x = x - \displaystyle\frac{x^3}{3!} + \displaystyle\frac{x^5}{5!} - \displaystyle\frac{x^7}{7!} + ...\\\\\sin x = x - \displaystyle\frac{x^3}{6} + \displaystyle\frac{x^5}{120} - \displaystyle\frac{x^7}{5040} + ...

3 0
3 years ago
The variance of a distribution is 195. What is the standard deviation, rounded to the nearest thousandth?
stiks02 [169]

Given:

The variance of a distribution = 195.

To find:

The standard deviation, rounded to the nearest thousandth.

Solution:

Standard deviation of a distribution is the square root of the variance of the distribution.

Here, the standard deviation of the distribution is

S.D.=\sqrt{195}

S.D.=13.96424

S.D.\approx 13.964

Therefore, the standard deviation is 13.964.

8 0
3 years ago
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