Question

Frankie wants to build a path from one corner of his yard to the opposite corner. His yard measures 20 ft. x 32 ft. What will be the length of his path to the nearest tenth of a foot?

Answer 1

Answer:

≈37.7 feet

Step-by-step explanation:

I'm assuming he goes diagonally.

We can form a triangle with legs 20 feet and 32 feet.

Using the Pythagorean Theorem, we get:

$20^2+32^2=c^2\\400+1024=c^2\\1424=c^2\\c^2=1424\\c=\sqrt{1424}$

c≈37.7

Answer 2

Answer: 37.7 ft

Step-by-step explanation:

20^2 + 32^2 = C^2 where c squared is the distance of the diagonal distance that  he wants to walk.

20^2 +32^2 =c^2

400 +1024 =c^2

1424 = c^2

c= 37.7359  rounded to the nearest tenth of a foot is 37.7