1. 4
2. 8
These are the only possible answers
For the first one, you did good. I will just suggest a couple things.
Statement Reason
JK ≅ LM Given
<JKM ≅ < LMK Given (You did both of these steps so well done.)
MK ≅ MK Reflexive Property (Your angle pair is congruent but isn't one of the interior angle of the triangles you are trying to prove.)
ΔJMK ≅ ΔLKM SAS
Problem 2: (You also have a lot of great stuff here.)
Statement Reason
DE ║ FG Given
DE ≅ FG Given
<DEF≅<FGH Given
<EDF≅<GFH Corresponding Angles (You don't need to know that F is the midpoint but you got corresponding angle pair which is correct.)
ΔEDF≅ΔGFH ASA
<DFE≅<FHG CPCTC
The answer for this is A.(3,1).
hope this helps
Answer
144
Step-by-step explanation:
12*12
Answer: YES
Step-by-step explanation:
We need to write out the expressions
P= {m}
Q= {n}
R= {m+n}
If 2m=n then we can say;
P= {½n} Q= {n} & R= {³/²n}
It is obvious that the smaller number in Q is greater than the largest number in P
We can make some assumptions.
Let n= (x,y,z)
Consequently,
P={½x,½y,½z} Q={x,y,z} and R= {1.5x,1.5y,1.5z}
Therefore the median will be the middle element,
Median of P= ½y
Median of Q = y
Median of R = 1.5y
And 1.5y>1.5y
Then we can agree that the median of R is greater than the median of both P and Q
