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madam [21]
3 years ago
5

2. A geological study indicates that an exploratory oil well drilled in a particular region should strike oil with probability 0

.20. Find the probability that the third oil strike comes on the fifth well drilled.
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
8 0

Answer:

3.07% probability that the third oil strike comes on the fifth well drilled.

Step-by-step explanation:

For each oil drill, there are only two possible outcomes. Either there is a strike, or there is not. The probability that oil is striken in a trial is independent of other trials. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Strike oil with probability 0.20.

This means that p = 0.2

Find the probability that the third oil strike comes on the fifth well drilled.

2 strikes on the first four drills(P(X = 2) when n = 4) and strike on the fifth(0.2 probability).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{4,2}.(0.2)^{2}.(0.8)^{2} = 0.1536

0.2*0.1536 = 0.0307

3.07% probability that the third oil strike comes on the fifth well drilled.

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Nookie1986 [14]

(\frac{g}{f})(3)=\frac{-13}{21}\\

2/3 will not be included in the domain of g/f

Step-by-step explanation:

Given functions are:

g(x) =-2x^2+5\\f(x)=9x-6

We have to calculate (f/g)(x) first

The steps will be as follows:

(\frac{g}{f})(x)=\frac{g(x)}{f(x)}

Putting the values of functions

(\frac{g}{f})(x)=\frac{-2x^2+5}{9x-6}\\We\ have\ to\ find\ the\ value\ of\ (\frac{g}{f})(x)\ at\ 3\\So,\\(\frac{g}{f})(3)=\frac{-2(3)^2+5}{9(3)-6}\\(\frac{g}{f})(3)=\frac{-2(9)+5}{27-6}\\(\frac{g}{f})(3)=\frac{-18+5}{27-6}\\(\frac{g}{f})(3)=\frac{-13}{21}

Domain of g/f:

(\frac{g}{f})(x)=\frac{-2x^2+5}{9x-6}

The function will be undefined if the denominator is zero.

To find the domain we will put the denominator equal to zero

So,

9x-6=0\\Adding\ 6\ on\ both\ sides\\9x-6+6=0+6\\9x=6\\Dividing\ both\ sides\ by\ 9\\\frac{9x}{9}=\frac{6}{9}\\x=\frac{2}{3}

Hence, the function will be undefined on x=2/3 so 2/3 will not be included in the domain of (f/g)(x)

<u>Answer:</u>

(\frac{g}{f})(3)=\frac{-13}{21}\\

2/3 will not be included in the domain of g/f

Keywords: Domain, Operations on Functions

Learn more about functions at:

  • brainly.com/question/4767370
  • brainly.com/question/4770453

#LearnwithBrainly

8 0
3 years ago
A flask contains 12% acid solution and the remaining volume is water. If the flask is 8.52 inches high and the diameter is 3.71
Tamiku [17]

Answer:

Percent of water in the mixture=88%

Which is 81.07 square inches of the total volume

Step-by-step explanation:

Volume of the flask=πr^2h

π=3.142

radius=diameter/2

=3.71/2

=1.855

height=8.52 inches

Volume of the flask=πr^2h

=3.142*(1.855)^2*8.52

=3.142*3.441025*8.52

=92.115688686

Approximately 92.12 square inches

Flask contains 12% acid solution and the remaining volume is water

Percentage of water =Total percentage - acid solution percentage

=100%-12%

=88%

Percentage of Water =88%

Percentage of the mixture by volume is water=88% of the total volume

=88/100*92.12

=81.0656 square inches

Approximately 81.07 square inches

6 0
4 years ago
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