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Tatiana [17]
4 years ago
11

Am I right about this because my friend says I'm not plz help

Mathematics
2 answers:
jeka57 [31]4 years ago
5 0
You are right!!!!!!!!!!!!
Ierofanga [76]4 years ago
4 0
You literally posted this twice...
You might be interested in
List from smallest to largest 7/12 1/2 2/3 4/10 1/6​
Vlad1618 [11]

Answer:

So if you're having difficulty visualizing the differences, you can rewrite them so they all have the same denominator

7/12 = 35/60

1/2 = 30/60

2/3 = 40/60

4/10 = 24/60

1/6 = 10/60

So now it's easier to see how they compare to each other.

10/60, 24/60, 30/60, 35/60, 40/60

And then simplify them or just refer to what they were before

1/6, 4/10, 1/2, 7/12, 2/3

I hope this helps!

3 0
3 years ago
A financial talk show host claims to have a 55.3 % success rate in his investment recommendations. You collect some data over th
baherus [9]

Answer:

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

Step-by-step explanation:

For each recommendation, there are only two possible outcomes. Either it was a success, or it was a failure. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.553, n = 10

If the claim is correct and the performance of recommendations is independent, what is the probability that you would have observed 4 or fewer successful:

This is

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.553)^{0}.(0.447)^{10} = 0.0003

P(X = 1) = C_{10,1}.(0.553)^{1}.(0.447)^{9} = 0.0039

P(X = 2) = C_{10,2}.(0.553)^{2}.(0.447)^{8} = 0.0219

P(X = 3) = C_{10,3}.(0.553)^{3}.(0.447)^{7} = 0.0724

P(X = 4) = C_{10,4}.(0.553)^{4}.(0.447)^{6} = 0.1567

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0003 + 0.0039 + 0.0219 + 0.0724 + 0.1567 = 0.2552

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

3 0
3 years ago
In a certain herd of 24 elephants there are 13 males. How many females are
aleksklad [387]
C is your possible answer. You are trying to find how many females.
4 0
3 years ago
5 1/10-1 7/10=<br><br>A.3 3/5<br>B.6 4/5<br>C.3 2/5<br>D. 3 3/10<br><br>​
Alenkasestr [34]
The answer is C

You're welcome
6 0
3 years ago
John and Gary share a workload. At a certain point, John worked 2 more hours than Gary. The next day, John has worked 4 of Gary’
il63 [147K]
If these both men were working at normal hours, and then, (John) worked "2 more hours" than Gary has, this would just mean that he has worked more.

x+2= x+2.

Now if John has worked the double amount, 4 more times than Gary's usual hours, this would mean something quite different.

Then the expression would look like, (x+2×4x)

We don't know how many hours are the "usual hours", this is what "x" would then represent.

John has then worked (4×2+x) more hours than Gary.

Your answer: (4×2+x)
4 0
3 years ago
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