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3 years ago

Using the discriminant, how many real solutions does the following quadratic

Mathematics

1 answer:

vazorg [7]3 years ago

5 0

Answer:

D one real solution

Step-by-step explanation:

x^2 - 8x + 16 = 0

This is in the form

ax^2 +bx + c = 0

so we can use the discriminant to determine the number of solutions

b^2 -4ac

(-8)^2 -4(1)(16)

64 - 64

Since the discriminant is zero, there is one real solution.

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You want to do a quick estimate to the ones place of the sum of the following set of data. Pick the correct estimation.

frez [133]

Answer:16

Step-by-step explanation:

3.5 - 4

6.7 - 7

3.2 - 3

1.7 - 2

Add those up and you get 16

3 0

2 years ago

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Let X1, . . . ,Xn be an i.i.d. random sample from a N(0, 1) population. Define Y1 = 1 n n X i=1 Xi , Y2 = 1 n n X i=1 |Xi| . Cal

nalin [4]

For each $1\le i\le n$ , $E[X_i]=0$ , so that

$\displaystyle E[Y_1]=E\left[\frac1n\sum_{i=1}^nX_i\right]=\frac1n\sum_{i=1}^nE[X_i]=0$

Meanwhile,

$\displaystyle E[Y_2]=\frac1n\sum_{i=1}^nE[|X_i|]$

Each of the $X_i$ have PDF

$f_{X_i}(x)=\dfrac1{\sqrt{2\pi}}e^{-x^2/2}$

for $x\in\Bbb R$ . From this we get

$E[|X_i|]=\displaystyle\frac1{\sqrt{2\pi}}\int_{-\infty}^\infty|x|e^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}\int_0^\infty xe^{-x^2/2}\,\mathrm dx=\sqrt{\frac2\pi}$

$\implies E[Y_2]=n\sqrt{\dfrac2\pi}$

8 0

2 years ago

Is 1/10, 1/4, and 1/8 more or less than 1/2

ryzh [129]

Answer:

They are less than 1/2

Step-by-step explanation:

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3 years ago

Which Statement about 4(x-3) is True?

Sophie [7]

Answer: it’s b because if you times that by anything it will always be a product I think

Step-by-step explanation:

8 0

3 years ago

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Please help!!!!<br> I desperately need the correct answer I’ve been trying all day!

zysi [14]

Answer:14708

Step-by-step explanation:Exponential Functions:

y=abxy=ab^x this is not right not correct

y=ab

a=starting value = 13000a=\text{starting value = }13000

a=starting value = 13000

r=rate = 2.5%=0.025r=\text{rate = }2.5\% = 0.025

r=rate = 2.5%=0.025

Exponential Growth:\text{Exponential Growth:}

Exponential Growth:

b=1+r=1+0.025=1.025b=1+r=1+0.025=1.025

b=1+r=1+0.025=1.025

Write Exponential Function:

y=13000(1.025)xy=13000(1.025)^x

y=13000(1.025)

Put it all together

Plug in time for x:\text{Plug in time for x:}

Plug in time for x:

y=13000(1.025)5y=13000(1.025)^{5}

y=13000(1.025)

y=14708.30677y= 14708.30677

y=14708.30677

Evaluate

y≈14708y\approx 14708

y≈14708

5 0

3 years ago

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