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3 years ago

Subtract 5x+10 from 2x-6 please answer

Mathematics

1 answer:

Ghella [55]3 years ago

3 0

Answer:

-3x-16

Step-by-step explanation:

(2x-6)-(5x+10)

2x-6-5x-10

2x-5x-6-10

-3x-6-10

-3x-16

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Claire accepted a new job at a company with a contract guaranteeing annual raises. Let S

TiliK225 [7]

Answer:

6 years

Step-by-step explanation:

First, you need to write an equation for this problem. I'll write it in slope intercept:

y = mx + b

where m is the slope and b is the y-intercept

To find m, do (change in y/change in x):

using (2, 59000) and (5, 72500),

(72500 - 59000) / (5 - 2)

= 13500 / 3

= 4500

So we have y = 4500x + b

To find b, plug in one of the points into the equation with the slope:

using (2, 59000),

y = 4500x + b

59000 = 4500(2) + b

59000 = 9000 + b

50000 = b

So now you have an equation: y = 4500x + 50000. Now that there is an equation, just insert the given y-value and solve:

when y = 77000

y = 4500n + 50000

= 77000 = 4500x + 50000

= 27000 = 4500x

= 6 = x

So, when Claire's Salary is 77000, her number of years at the company is 6.

6 0

2 years ago

The average daily high temperature in °C) in Karachi, Pakistan, on the tth day of the year is

kvasek [131]

Answer:

The highest would be 34 degrees Celsius and the lowest would be 24 degrees Celsius.

Step-by-step explanation:

What I did was make a graph. The 29 in the beginning of the function represents the vertical shift, meaning the "midline" would be y = 29. The -5 after the 29 represents the amplitude. From there, you can go 5 under 29 (24 degrees Celsius) and 5 over 29 (34 degrees Celsius).

3 0

2 years ago

What does 7/18 estimate to 0,1/2,1

DiKsa [7]

Answer: 11/2

Step-by-step explanation:

7 0

2 years ago

For the following right triangle, find the side length x. Round your answer to the nearest hundredth.

Aleksandr-060686 [28]

Answer:

$\sqrt{113}$ = x

Step-by-step explanation:

In right triangles the sum of square length of two legs is equal to square length of hypotenuse:

7^2 + 8^2 = x^2

49 + 64 = x^2 add like terms

113 = x^2 find the root for both sides

$\sqrt{113}$ = x

8 0

2 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

2 years ago