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Andre45 [30]
Answer:
the one real zero is in the interval (-1, 0)
Step-by-step explanation:
Descartes' rule of signs tells you there are 0 or 2 positive real zeros. Changing the signs of the odd-degree terms and applying that rule again tells you there is one negative real zero. At the same time, those coefficients (-3, -5, -5, +7) have a negative sum, so you know ...
f(-1) = -6
f(0) = +7
so there is a zero in the interval (-1, 0).
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You can try a few values between x=0 and x=10 to see what the function does in that part of the graph. You find ...
f(1) = 10
f(2) = 21
f(3) = 58
So, it is safe to conclude that there are no real zeros for x > 0.
The only real zero of f(x) is in the interval (-1, 0).
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I like to use a graphing calculator for problems like this.
Answer:
(D) 30pi inches
Step-by-step explanation:
First, we use the given volume, the given height, and the formula of the volume of a cylinder to find the radius of the base. Then we use the radius of the base to find the circumference of the base.
We set the formula equal to the volume and replace h with 30 in.
Divide both sides by 30pi in.
Take the square root of each side.
The radius of the base is 15 in.
Now we use the radius of the base and the formula of the circumference of a circle to find the answer.
18 per adult, 9 per child total equals 2,475,00 and the hold of guest is 150
Answer:
The measure of the third angle is equal to 34°
Step-by-step explanation:
Given that,
The measure of angle 1 is 50°.
The measure of angle 2 is 96°
We need to find the measure of the third angle. We know that the sum of angles of a triangle is equal to 180°. So,
x+50+96=180
x+146=180
x = 180-146
x = 34°
So, the measure of the third angle is equal to 34°.
Strange question, as normally we would not calculate the "area of the tire." A tire has a cross-sectional area, true, but we don't know the outside radius of the tire when it's mounted on the wheel.
We could certainly calculate the area of a circle with radius 8 inches; it's
A = πr^2, or (here) A = π (8 in)^2 = 64π in^2.
The circumference of the wheel (of radius 8 in) is C = 2π*r, or 16π in.
The numerical difference between 64π and 16π is 48π; this makes no sense because we cannot compare area (in^2) to length (in).
If possible, discuss this situatio with your teacher.
