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3 years ago

The diameter of a round dinner plate is 10 inches. What's the area of the plate?

Mathematics

1 answer:

topjm [15]3 years ago

5 0

A= pi times r*r so if you are using 3.14 as pi the answer is 78.5 because 5x5=25
25x3.14=78.5

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PLEASE HELP I PUT THE PROBLEM AS A PICTURE PLEASE ANSWER WILL GIVE 30 POINTS SHOW WORK

dem82 [27]

Answer:

$\huge\boxed{9}$

Step-by-step explanation:

$\sf (2^8 * 3^{-5} * 6^0)^{-2 } (\frac{3^{-2}}{2^3} )^4*2^{28}$

Rule of exponents $a^0 = 1$ , $1/a^m = a^{-m}$

=> $\sf 2^{8*-2} * 3 ^{-5*-2} * 3 ^{-2}* 2^{-3*4} * 2^{28}$

=> $\sf 2 ^ {-16} * 3^{10} * 3^{-8} * 2 ^{-12}* 2^{28}$

Combining same bases

=> $\sf 2 ^ {-16} * 2 ^{-12}* 2^{28}* 3^{10} * 3^{-8}$

When bases are same , powers are to be added

=> $\sf 2 ^{-16-12+28} * 3^{10-8}$

=> $\sf 2^{-28+28} * 3^2$

=> $\sf 2^0 * 3^2$

=> $\sf 3^2$

=> 9

8 0

3 years ago

A principal randomly chose 30 students from grade 8. Of these students, 9 were wearing watches. Based on this information, what

hram777 [196]

Answer:

im pretty sure 36

Step-by-step explanation:

if you do 120 devided by 30 you get 4, then u just multipy by 9 which is 36.

5 0

3 years ago

I need help with this will be giving 10 points

dusya [7]

Answer:

Its D

Step-by-step explanation:

Both triangles are obtiuse rubber goose green mouse guva juice

8 0

2 years ago

Read 2 more answers

Math problem I need help on

JulijaS [17]

Answer:I think the answer is

1. x=8

Step-by-step explanation:

1. X=8

2. X=1⅓

3. 0x=-12

4. -8x=0

5. 0x=24

8 0

3 years ago

Which of the following functions gives the length of the base edge, a(v), of a right square pyramid that is 8 inches tall as a f

Reil [10]

Answer:

$\large\boxed{a(V)=\sqrt{\dfrac{3V}{8}}}$

Step-by-step explanation:

The formula of a volume of a square pyramid:

$V=\dfrac{1}{3}a^2h$

a - base edge

h - height of a pyramid

We have H = 8in.

Substitute and solve for a:

$\dfrac{1}{3}a^2(8)=V\\\\\dfrac{8}{3}a^2=V\qquad\text{multiply both sides by}\ \dfrac{3}{8}\\\\\dfrac{3\!\!\!\!\diagup^1}{8\!\!\!\!\diagup_1}\cdot\dfrac{8\!\!\!\!\diagup^1}{3\!\!\!\!\diagup_1}a^2=\dfrac{3}{8}V\\\\a^2=\dfrac{3V}{8}\Rightarrow a=\sqrt{\dfrac{3V}{8}}$

3 0

3 years ago