Answer:
Probability of getting a number which is not 2 = 7/8
Step-by-step explanation:
Given;
Total number of faces = 8
Number of face with 2 = 1
Number of face with 3 = 2
Number of face with 4 = 1
Number of face with 7 = 3
Number of face with 9 = 1
Find:
Probability of getting a number which is not 2
Computation:
Probability of not an event = 1 - [Number of favourable outcomes / Total number of outcomes]
Probability of getting a number which is not 2 = 1 - [1/8]
Probability of getting a number which is not 2 = [8-1] / 8
Probability of getting a number which is not 2 = 7/8
Answer: Explanation:First, let's call the number of 2 cent coins: tNext, let's call the number of 5 cent coins: fWe can then write to equations from the information in the problem.Equation 1: t+f=40Equation 2: 0.02t+0.05f=1.55Step 1) Solve the first equation for t:t+f=40t+f−f=40−ft+0=40−ft=40−fStep 2) Substitute (40−f) for t in the second equation and solve for f:0.02t+0.05f=1.55 becomes:0.02(40−f)+0.05f=1.55(0.02×40)−(0.02×f)+0.05f=1.550.80−0.02f+0.05f=1.550.80+(−0.02+0.05)f=1.550.80+0.03f=1.550.80−0.80+0.03f=1.55−0.800+0.03f=0.750.03f=0.750.03f0.03=0.750.030.03f0.03=25f=25Step 3) Substitute 25 for f in the solution to the first equation at the end of Step 1 and calculate t:t=40−f becomes:t=40−25t=15The Solution Is:There are:15 two cent coins25 five cent coins
Step-by-step explanation:
Answer:
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Step-by-step explanation:
The answer to the equation is 8
Answer:


Step-by-step explanation:
<h3>Question-1:</h3>
so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,
to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

to solve the equation can consider the quadratic formula given by

so let our a,b and c be -4.9,229 and 346 Thus substitute:

remove parentheses:

simplify square:

simplify multiplication:

simplify Substraction:

by simplifying we acquire:

since time can't be negative

hence,
at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs
<h3>Question-2:</h3>
to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

let a and b be -4.9 and 229 respectively thus substitute:

simplify which yields:

now plug in the maximum t to the function:

simplify:

hence,
about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?