1 hour = 60 minutes.
Convert the minutes to decimals by diving by 60
30/60 = 0.5
2 hours and 30 minutes = 2.5 hours
45/60 = 0.75
5 hours 45 minutes = 5.75 hours
15/50 = 0.25
3 hours 15 minutes = 3.25 hours
Ow add all the hours:
2.5 + 5 + 5.75 + 3.25 = 16.5 hours
Answer: B. 16.50
Answer:
Step-by-step explanation:
Statements Reasons
1). SP ≅ TP 1). Given
2). PQ bisects ∠SPT 2). Given
3). ∠SPQ ≅ ∠TPQ 3). Definition of angles bisector
4). PQ ≅ PQ 4). Reflexive property of congruence
5). ΔSPQ ≅ ΔTPQ 5). SAS property of congruence
Answer:
$2, $4, $10, $20
Step-by-step explanation:
1*2=2
2*2=4
5*2=10
10*2=20
<span>Use the slope intercept form y=<span><span>mx</span>+b, </span></span><span>where </span><span>m</span><span> is the slope and </span><span>b</span><span> is the y-intercept. So with saying that plug your problem in so y = -3x+3 so your answer would be m=-3 which is the slope.
~Hope this Helps! Good Luck!~
</span>
Answer:
Rachel
Step-by-step explanation:
We need to measure how far (towards the left) are the students from the mean in<em> “standard deviations units”</em>.
That is to say, if t is the time the student ran the mile and s is the standard deviation of the class, we must find an x such that
mean - x*s = t
For Rachel we have
11 - x*3 = 8, so x = 1.
Rachel is <em>1 standard deviation far (to the left) from the mean</em> of her class
For Kenji we have
9 - x*2 = 8.5, so x = 0.25
Kenji is <em>0.25 standard deviations far (to the left) from the mean</em> of his class
For Nedda we have
7 - x*4 = 8, so x = 0.25
Nedda is also 0.25 standard deviations far (to the left) from the mean of his class.
As Rachel is the farthest from the mean of her class in term of standard deviations, Rachel is the fastest runner with respect to her class.
