Pt. 2 to the my first question
1 answer:
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Answer:
Given: A parallelogram EFGH in which diagonals intersect at point J.
To Find: A segment congruent to EJ.
Solution: In parallelogram EFGH
Point of intersection of Diagonals EG and FH are point J.
As we know diagonals of parallelogram bisect each other.
So, EJ=JG and FJ=JH
∵ Solution is EJ≅ JG
