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2 years ago

How do I solve for the fourth term in this sequence?

Mathematics

1 answer:

tatiyna2 years ago

3 0

Answer:

Step-by-step explanation:

d(1) = 13

d(n) = d(n - 1) + 17

where

n is the nth term

To find the 4th term we must first find the second term use it to find the 3rd term and use the 3rd term to find the 4th term

So we have

That's d(2)

We have

d(2) = d(2-1) + 17

d(2) = d(1) + 17

But d(1) = 13

d(2) = 13 + 17 = 30

That's

d(3) = d(3 - 1) + 17

d(3) = d(2) + 17

d(3) = 30 + 17 = 47

We have

d(4) = d(4 - 1) + 17

d(4) = d(3) + 17

d(4) = 47 + 17

We have the final answer as

Hope this helps you

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The mean number of daily surgeries at a local hospital is 6.2. Assume that surgeries are random, independent events. (a) The cou

Scilla [17]

Answer:

a) correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2 surgeries in a given day is 0.0536

Step-by-step explanation:

Given data:

mean number is given as 6.2

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

we know that variance is given as $\sigma^2 = mean = 6.2$

hence, standard deviation is given as $\sqrt{6.2} = 2.48998$

thus standard deviation is 2.49

correct option is

Poisson distribution is 6.2 and standard deviation is 2.49

b) probability for only 2 or less than 2 surgeries in a given day is

$P(X \leq 2) = P(X =0) + P(X =1) + P(X =2)$

$= \frac{e^{-6.2} 6.2^0}{0!} +\frac{e^{-6.2} 6.2^1}{1!} +\frac{e^{-6.2} 6.2^2}{2!}$

= 0.002029 + 0.012582+ 0.039006

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= 0.0536

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2 years ago

The floor of a room is being covered with tile. An area one half

tangare [24]

Answer:

Only the floor area $\frac{3}{8}$ has been covered

Step-by-step explanation:

Assuming that the floor of the room is rectangular, then its area is equal to the product of its length times its width.

$A = lw$

Let's now call A 'the area that was covered with tiles.

We know that half the length was covered, then:

$l' = \frac{1}{2}l$

$w' = \frac{3}{4}w$

So:

$A' = \frac{1}{2}l(\frac{3}{4}w)$

$A' = \frac{3}{8}lw$

Finally:

$A' = \frac{3}{8}A$

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