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choli [55]
3 years ago
5

How do I solve for the fourth term in this sequence?

Mathematics
1 answer:
tatiyna3 years ago
3 0

Answer:

<h2>d(4) = 64</h2>

Step-by-step explanation:

d(1) = 13

d(n) = d(n - 1) + 17

where

n is the nth term

To find the 4th term we must first find the second term use it to find the 3rd term and use the 3rd term to find the 4th term

So we have

<u>For the 2nd term</u>

That's d(2)

We have

d(2) = d(2-1) + 17

d(2) = d(1) + 17

But d(1) = 13

d(2) = 13 + 17 = 30

<u>For the 3rd term d(3)</u>

That's

d(3) = d(3 - 1) + 17

d(3) = d(2) + 17

d(3) = 30 + 17 = 47

<u>For the 4th term that's d(4)</u>

We have

d(4) = d(4 - 1) + 17

d(4) = d(3) + 17

d(4) = 47 + 17

We have the final answer as

<h3>d(4) = 64</h3>

Hope this helps you

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Step-by-step explanation:

A left Riemann sum approximates a definite integral as:

\int\limits^b_a {f(x)} \, dx \approx \sum\limits_{k=1}^{n}f(x_{k}) \Delta x \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times (k-1)

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