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Nutka1998 [239]
3 years ago
10

Four and five is how much greater than one hundred sixty-seven thousandth

Mathematics
1 answer:
andrey2020 [161]3 years ago
6 0

Answer:

Step-by-step explanation:

3456

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Which equation represents a circle with the same radius as the circle shown but with a center (-1, 1)
mylen [45]

Answer:

Option 4: (x+1)^2+(y-1)^2 = 16

Step-by-step explanation:

The radius of the given circle in attached picture is: 4 units

The center is denoted by (h,k) = (-1,1)

So,

The standard form of equation with center at (h,k) and radius r

(x-h)^2 + (y-k)^2 = r^2

Putting the values

(x-(-1))^2 + (y-1)^2 = 4^2

(x+1)^2+(y-1)^2 = 16

Hence option number 4 is correct ..

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4 years ago
List the angles in order from smallest to largest 2.8 3.2 and 3
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2.8 3.2 and lastly 3.
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3 years ago
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3 years ago
Help me with this please!!!!!!
castortr0y [4]

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\huge\mathcal\red{here's \:  your \:  solution..} \\  \\  \cos = base \div hypotenuse \:  \\  \\  \cos(60)  = 1 \div 2 \\  \\  \cos = a \div 14 \\  \\ a \div 14 = 1 \div 2 \\  \\ a = 14 \div2 \\  \\ a = 7 \: cm \\  \\ \huge\mathfrak\green{hope \: it \: helps..}

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3 years ago
The Environmental Protection Agency (EPA) has contracted with your company for equipment to monitor water quality for several la
max2010maxim [7]

Answer:

36.58% probability that one of the devices fail

Step-by-step explanation:

For each device, there are only two possible outcomes. Either it fails, or it does not fail. The probability of a device failling is independent of other devices. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A total of 15 devices will be used.

This means that n = 15

Assume that each device has a probability of 0.05 of failure during the course of the monitoring period.

This means that p = 0.05

What is the probability that one of the devices fail?

This is P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{15,1}.(0.05)^{1}.(0.95)^{14} = 0.3658

36.58% probability that one of the devices fail

7 0
3 years ago
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