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AleksandrR [38]
2 years ago
14

An object falls 18ft in 2 seconds. Knowing the distance varies directly with the square of the time of the fall how long does it

take an object to fall 79 feet
Mathematics
1 answer:
AVprozaik [17]2 years ago
7 0

Answer:

t=4.19 seconds

Step-by-step explanation:

Distance varies directly with the square of the time of the fall

It means,

D=kt^2

18ft in 2 seconds

D=kt^2

18=k*2^2

18=4k

k=18/4

=9/2

k=9/2

D=kt^2

D=79feet

79=9/2t^2

t^2=79÷9/2

t^2=79×2/9

=158/9

t=√158/√9

t=12.57/3

t=4.19 seconds

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Vilka [71]

Answer: The side of the playground is around 10 meters long

Step-by-step explanation:

use the diagonal as the hypotenuse of a right triangle, where the sides of the square form the legs of said triangle.

Usually

a^{2} +b^{2} =c^{2}

since we know a and b are the same length (sides of a square are congruent) we would have

a^{2} +a^{2} =c^{2} \\2a^{2} =c^{2}

We know that c is 14 so

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Step-by-step explanation:

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The length of the longer leg of a right triangle is 20 inches more than twice the length of the shorter leg. The length of the h
Alex17521 [72]

Answer:

Step-by-step explanation:

Let x represent the length of the hypotenuse.

Let y represent the length of the the shorter leg.

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The length of the longer leg of a right triangle is 20 inches more than twice the length of the shorter leg. It means that

z = 2y + 20

The length of the hypotenuse is 22 inches more than twice the length of the shorter leg. It means that

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Therefore,

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5y² - 4y²+ 80y - 88y + 400 - 484

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Step-by-step explanation:

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