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jeka94
4 years ago
15

Can you help me on this please(:

Mathematics
2 answers:
S_A_V [24]4 years ago
6 0
I can solve it without area mode:
I think it's 25,528
Sergio039 [100]4 years ago
6 0
Here u go, hope u get it, if not text me

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Amir lent Rs. 600 to Hameed for 2 yrs and Rs.150 to Aman for 4 yrs and recievd altogether from both rs.90 as simple intrest.The
Alja [10]
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5 0
4 years ago
Analyze the diagram below and answer the question that follows.
Anna35 [415]

Answer:

The right statement is sin(J) = cos(L) ⇒ answer D

Step-by-step explanation:

* Lets describe the figure

- LKJ is a right triangle, where K is a right angle

∵ m∠K = 90°

∵ LJ is opposite to angle K

∴ LJ is the hypotenuse

∵ LJ = 219

∵ KJ = 178

- By using Pythagoras Theorem

∵ (LJ)² = (LK)² + (KJ)²

∴ (219)² = (LK)² + (178)² ⇒ subtract (178)² from both sides

∴ (LK)² = (219)² - (178)²

∴ (LK)² = 16277

∴ LK = √16277 = 127.58

* Lets revise how to find the trigonometry function

# sin Ф = opposite/hypotenuse

# cos Ф = adjacent/hypotenuse

# tan Ф = opposite/adjacent

∵ LK is the opposite side to angle J

∵ LJ is the hypotenuse

∵ sin(J) = LK/LJ

∵ LK = 127.58 , LJ = 219

∴ sin(J) = 127.58/219 = 0.583

∵ LK is the adjacent side to angle L

∵ LJ is the hypotenuse

∵ cos(L) = LK/LJ

∵ LK = 127.58 , LJ = 219

∴ cos(L) = 127.58/219 = 0.583

∴ sin(J) = cos(L)

* The right statement is sin(J) = cos(L)

7 0
3 years ago
The sum of three consecutive odd integers is 17 less than four times the smallest integer. Find the integers.
lisabon 2012 [21]

Answer:

23, 25, 27

Step-by-step explanation:

n + (n+2) + (n+4) = 4n - 17

3n + 6 = 4n - 17

3n - 4n = -17 - 6

-n = -23

n = 23

therefore,

23, 25, 27 are the 3 consecutive odd integers

6 0
3 years ago
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