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3 years ago

What is the simplest form for 9/36

Mathematics

2 answers:

Lubov Fominskaja [6]3 years ago

5 0

1/4 is the answer. Hope i helped

Sauron [17]3 years ago

3 0

9/36 in the simplest form is 1/4

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What does (26/13).(-7)+14-4=

Bond [772]

Answer:

-4

Step-by-step explanation:

1. Always start with the parenthesis. (26/13) = 2

2. Then multiply. 2*-7 = -14

3. After, you add 14 to your precious answer (-14) then subtract 4.

-14 + 14 = 0 - 4 = -4

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2 years ago

Write the equation in slope-intercept form.<br> y−1=45(x+5)

aleksandrvk [35]

Answer:

y=45x+226

Step-by-step explanation:

hope that's what you're looking for

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2 years ago

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7. 3.278 × 0.145

crimeas [40]

Answer:

7. 0.47531

8. 98.7252

9. 13238.984

10. 0.00757576

11. 15011.4286

12. Proper

13. Improper

14. 11/4

15. 33/7

16. 1 4/8 or 1 1/2

17. 3 1/6

Step-by-step explanation:

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2 years ago

Round 65754.59 to the nearest tenth

V125BC [204]

65754.6 because the 9 in the hundreds place bumps up the five in the tenths

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2 years ago

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A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

Pachacha [2.7K]

Answer: B. 0.59 plus or minus 0.090

Step-by-step explanation:

The confidence interval of population proportion is given by :-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

Given : Sample size : $n=200$

The proportion of students are receiving financial aid : $hat{p}=\dfrac{118}{200}=0.59$

Significance level : $\alpha: 1-0.99=0.01$

Critical value : $z_{\alpha/2}=2.576$

Then, the confidence interval of population proportion is given by :-

$0.59\pm (2.576)\sqrt{\dfrac{0.59(1-0.59)}{200}}\\\\=0.59\pm0.0895877841673\\\\\approx0.59\pm0.090$

Hence, a 99% confidence interval to estimate the true proportion of students on financial aid = 0.59 plus or minus 0.090

8 0

2 years ago