Ask question

Ask question

All categories

3 years ago

13

Somebody help me 33 please!!!

2 answers:

Lubov Fominskaja [6]3 years ago

8 0

The circle is divided in to 6 pieces.

one of the pieces is shaded.

The shaded portion/the number of pieces

1/6

olga2289 [7]3 years ago

3 0

33. 1/6 is the answer

You might be interested in

UT bisects WV. WV = ? <br><br> A. SV<br><br> B. 2(SV)<br><br> C. UT<br><br> D. none of the above

ValentinkaMS [17]

2(sv) is the answer for the question

4 0

3 years ago

How many 135-inch-thick books can fit on a 1412-inch-long bookshelf?

swat32

9x135 = 1,215
10x135 = 1,350
11x135 = 1,485

Therefore, your answer would be 10.

4 0

1 year ago

Q is the midpoint of line segment PR. PR=9x-31 and QR=43 ; find x

bulgar [2K]

notice that, if Q is the midpoint of PR, that simply means that PQ = QR = 43.

$\bf \boxed{P}\underset{\leftarrow 9x-31 \to }{\stackrel{\stackrel{\downarrow }{43}}{\rule[0.35em]{10em}{0.25pt}}Q\stackrel{43}{\rule[0.35em]{10em}{0.25pt}}}\boxed{R}
\\\\\\
9x-31=43+43\implies 9x-31=86\implies 9x=117
\\\\\\
x=\cfrac{117}{9}\implies x=13$

5 0

3 years ago

on a cold January day, Kiara noticed that the temperature dropped 21 degrees over the course of the day -9°C write and solve an

Readme [11.4K]

Answer:

The temp started at 12.

Step-by-step explanation:

The temp dropped 21 degrees to -9.

Let t be the old temp.

-9 = t - 21

t = 12

3 0

3 years ago

The endpoints of one diagonal of a rhombus are (-7, -2) and (-1, -4). If the coordinates of the 3rd vertex are (-6, -9), what ar

podryga [215]

The coordinates of the 4th vertex of the rhombus are (-2,3)

<h3>How to determine the coordinates of the 4th vertex?</h3>

The diagonals are given as:

(-7, -2) and (-1, -4)

The 3rd vertex is given as: (-6,-9)

Calculate the distance between the vertices of the diagonals and the 3rd vertex using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}$

So, we have:

$d_1 = \sqrt{(-7 + 6)^2 + (-2 + 9)^2} =\sqrt{50$

$d_2 = \sqrt{(-1 + 6)^2 + (-4 + 9)^2} =\sqrt{50$

Let the 4th vertex be (x,y)

So, we have:

$d_3 = \sqrt{(-7 - x)^2 + (-2 - y)^2} =\sqrt{50$

$d_4 = \sqrt{(-1 - x)^2 + (-4 - y)^2} =\sqrt{50$

Equate d3 and d4

$\sqrt{(-1 - x)^2 + (-4 - y)^2} = \sqrt{(-7 - x)^2 + (-2 - y)^2}$

Take the square of both sides

$(-1 - x)^2 + (-4 - y)^2 = (-7 - x)^2 + (-2 - y)^2$

Expand

$1 + 2x + x^2 + 16 + 8y + y^2 = 49 + 14x + x^2 + 4 + 4y + y^2$

Evaluate the like terms

1 + 2x + 16 + 8y = 49 + 14x + 4 + 4y

Collect like terms

14x - 2x + 4y - 8y = 1 + 16 - 49 - 4

12x - 4y = -36

Divide through by 4

3x - y = -9

Next, we test the options in the above equation

Point (-8,13) means x = -8 and y = 13

So, we have:

3x - y = -9

3(-8) - 13 = -9

-37 = -9 --- this is false

Point (-2, 3) means x = -2 and y = 3

So, we have:

3x - y = -9

3(-2) - 3 = -9

-9 = -9 --- this is true.

Hence, the coordinates of the 4th vertex are (-2,3)

Read more about rhombus at:

brainly.com/question/20627264

#SPJ1

8 0

1 year ago