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Alenkasestr [34]

3 years ago

15

A candidate who runs for the U.S. House of Representatives must meet which of the following qualifications? A) at least 30 years

old
B) hold law degree
C) legal resident of state
D) U.S. citizen from birth

1 answer:

Lelechka [254]3 years ago

5 0

!!!!The Answer , !!! is D???!!!!!!

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In nuclear fission and fusion reactions mass is converted into energy. The average person in US uses around 100,000,000 J of ene

daser333 [38]

Answer:

a) The yearly energy consumption for a US population of 300 million is $3\times 10^{16} J/year$

b) The energy that would be released if a 60 kg person were converted entirely into energy is $5.4\times 10^{18}$ Joules.

c) 180 years would this amount of energy support a population of 300 million.

Explanation:

a) Average energy consumed by single person of US = 100,000,000 J/year

Then 300 million US citizen will consume:

300 million = 300 × 1,000,000 = $3\times 10^8$

The yearly energy consumption for a US population :

$100,000,000 J/year\times 3\times 10^8=3\times 10^{16} J/year$

The yearly energy consumption for a US population of 300 million is $3\times 10^{16} J/year$

b) $E = m\times c^2$

E = Energy from converted mass of m

c = speed of light

Given mass of person = m = 60 kg

$E=60 kg\times (3\times 10^8 m/s)^2 = 5.4\times 10^{18} J$

c) Energy calculated in part (b) = $E=5.4\times 10^{18} J$

The yearly energy consumption for a US population of 300 million in an year = $3\times 10^{16} J/year$

Let the that would be supported by $5.4\times 10^{18}$ Joules of energy be x.

$x\times 3\times 10^{16} J/year=5.4\times 10^{18} J$

$x=\frac{5.4\times 10^{18} J}{3\times 10^{16} J/year}=180 years$

180 years would this amount of energy support a population of 300 million.

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