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3 years ago

Find the total surface area of a cylinder with a height of 5 cm and radius of 2 cm. Leave your answer in terms of π.

Mathematics

2 answers:

Reil [10]3 years ago

6 0

Answer: the total surface area of the cylinder is 18π cm²

Step-by-step explanation:

The formula for determining the total surface area of a cylinder is expressed as

Total surface area = 2πr² + 2πrh

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

From the information given,

radius = 2 cm

Height = 5 cm

Therefore,

Area = (2 × π × 2²) + (2 × π × 5)

Area = 8π + 10π

Area = 18π

Olin [163]3 years ago

3 0

Answer:

28π cm2

Step-by-step explanation:

A=2πrh+2πr2

now you need to plug in

2 x π x 2 x 5 + 2 x π x 2 x 2

20 π + 8 π

28 π( since they ask you to leave the answer in terms of π.

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Un fabricante de ventanas cuadradas cobra a razón de 3 euros por cada metro de marco y 12 euros por el cristal, sean cuales sean

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The cost of the square windows is 3 euros per meter, and 12 euros for the crystal.

<h3>If a window has 2 meters side, how much would it cost? (A)</h3>

Notice that the window is a square, that means all four sides are congruent, so it has 8 meters in total, which would cost 24 euros plus the crystal. Therefore, the total cost of a window with 2 meters side is 24+12 = 36 euros.

Specifically, the function of the cost is: $C(x)=3x+12$ , where $x$ represents meters of sides. (C)

<h3>If we paid 60 euros, the dimensions are (B)</h3>

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The graph of the function is attached.

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3 years ago

Square RSTU is inscribed in circle P. Given the coordinates for the vertices of the square, find the equation of circle P.

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Answer:

$(x-2)^2+y^2=20$

Step-by-step explanation:

We want to find the equation of a circle P, and we know that the square RSTU is inscribed in the circle, this means that if we replace the points:

R(0,4) S(6,2) T(4,-4) and U(-2,-2) the equation must be verified.

Then, we have to replace the points in each option to see which one is the correct answer.

Option A: $(x-2)^2+y^2=68$

R(0,4):

$(x-2)^2+y^2=68\\(0-2)^2+4^2=68\\(-2)^2+16=68\\4+16=68\\20\neq 68$

We can see that R doesn't belong to the equation of the circle.

We could replace the rest of the points in the equation, but since we already know that R does not belong to the circle, we already know that it is not the right option.

Option B: $(x+2)^2+y^2=20$

R(0,4):

$(x+2)^2+y^2=20\\(0+2)^2+4^2=20\\2^2+4^2=20\\4+16=20\\20=20$

The point R(0,4) verifies the equation.

S(6,2):

$(x+2)^2+y^2=20\\(6+2)^2+2^2=20\\8^2+4^2=20\\64+16=20\\80\neq 20$

The point S doesn't belong to the equation of the circle, then we already know that this isn't the correct option.

Option C: $(x-2)^2+y^2=20$

R(0,4):

$(x-2)^2+y^2=20\\(0-2)^2+4^2=20\\(-2)^2+16=20\\4+16=20\\20=20$

The point R verifies the equation.

S(6,2):

$(x-2)^2+y^2=20\\(6-2)^2+2^2=20\\4^2+4=20\\16+4=20\\20=20$

The point S verifies the equation.

T(4,-4):

$(x-2)^2+y^2=20\\(4-2)^2+(-4)^2=20\\2^2+16=20\\4+16=20\\20=20$

The point T verifies the equation.

U(-2,-2):

$(x-2)^2+y^2=20\\(-2-2)^2+(-2)^2=20\\(-4)^2+4=20\\16+4=20\\20=20$

The point U verifies the equation.

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<em>We can see that the graph of the equation verifies the answer.</em>

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