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ankoles [38]
3 years ago
9

What amino acid sequence will be generated, based on the following mRNA codon sequence? 5' AUG-UCU-UCG-UUA-UCC-UUG 3'

Biology
1 answer:
miv72 [106K]3 years ago
4 0

Answer:

Met-Ser-Ser-Leu-Ser-Leu

Explanation:

mRNA have triplet codons and each triplet codon codes for an amino acid. An amino acid can be coded by many triplet codons but one amino acid can only code for a single amino acid.  

AUG is a start codon that codes for initiator amino acid called methionine. Serine can be coded by UCU, UCC, UCA, UGC, AGU, AGC triplet codon. leucine can be coded by UUA, UUG, CUU, CUC, CUA, CUG.

So the codon sequence 5' AUG-UCU-UCG-UUA-UCC-UUG 3' will generate Met-Ser-Ser-Leu-Ser-Leu amino acid sequence.

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