Answer:
3x-y=1 is in the form Ax+By=c
where A=3, B=-1, C=1
Step-by-step explanation:
we have to convert the equation y-5=3(x-2) to the form Ax + By = C.
the equation y-5=3(x-2) is in the form 
which is the point slope form of a straight line in cartesian coordinate.
where m is the slope of the line and
is the point through which the line is passing through.
therefore y-5=3(x-2) becomes y-5 = 3x-6
y-5+6=3x
y+1=3x
3x-y=1
this equation is in the form Ax+By=c
therefore comparing these two equations we get
A=3, B=-1, C=1
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Step-by-step explanation:
L = 6t+5
H = √t
A = L*H
= (6t+5) *√t = 6t√t + 5√t
A'(t) = 6t * 1/2*√t + √t * 6 + 5/2*√t
= 6t/2√t + 6√t + 5/2√t
Answer:
D. Y+5=-(1/2)*(x+3)
Step-by-step explanation:
Perpendicular Lines are those with the following condition:
y=a*x+b (1)
y=c*x+d (2)
Where 'a' and 'c' are the respective slope
If These two lines are perpendicular, then
a=- 1/c
Equation (1) for our case is written as y=2x-8, meaning that a=2 and b = -8
Using those principles we have that the slope for our needed line ('c') has to be -(1/2).
Now we most use the given point to find the remaining term of the equation (d) so, evaluate (-3,-5) in eq (2) to have this:
-5=(-1/2)*(-3)+d
resulting that d=-5-(3/2)
Eq (2) is written now as the following: y= (-1/2)*x - (5+3/2)
Rearranging terms, we have the following:
y+5=(-1/2)*x-(3/2)
where you can obtain a more pretty expression:
y+5=(-1/2)*(x+3)