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Verizon [17]
3 years ago
11

Plz, help ASAP!!!!!!!!!!! Thanks

Mathematics
2 answers:
Elena L [17]3 years ago
6 0

Answer:

TWO LINES THAT SHARE COMMON ENDPOINT ARE ALWAYS PERPENDICULAR

Lena [83]3 years ago
4 0

Answer:

Fourth one

Step-by-step explanation:

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((2x^9)(y^n))((4x^2)(y^10))=(8x^11)(y^20)
IgorLugansk [536]

We are given

((2x^9)(y^n))((4x^2)(y^{10}))=(8x^{11})(y^{20})

Firstly, we simplify left side

Left side is

((2x^9)(y^n))((4x^2)(y^{10}))

we will make all x terms together

and y terms together

(2x^9)(4x^2)(y^n)(y^{10})

2\times 4(x^9)(x^2)(y^n)(y^{10})

8(x^9)(x^2)(y^n)(y^{10})

we can multiply left side by using exponent rule

a^m\times a^n=a^{m+n}

8(x^{9+2})(y^{n+10})

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now, we can set them equal

(8x^{11})(y^{n+10})=(8x^{11})(y^{20})

Since, both sides have x,y and 8

and both are equal

so, their exponent must be equal

so, exponent of y must also be equal

we get

n+10=20

n=10................Answer


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