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3 years ago

Can I get a answer for it please

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

6 0

Answer:

25%

Step-by-step explanation:

There are 6+8+10 = 24 cookies

P ( chocolate chip) = number of chocolate chip/ total

= 6/24 = 1/4

Changing to percent

1/4 = 25/100 = 25%

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Please help me ASAP

stellarik [79]

Answer:

<em>The Graph is shown below</em>

Step-by-step explanation:

<u>The Graph of a Function</u>

Given the function:

$\displaystyle y=g(x)=-\frac{3}{2}(x-2)^2$

It's required to plot the graph of g(x). Let's give x some values:

x={-2,0,2,4,6}

And calculate the values of y:

$\displaystyle y=g(-2)=-\frac{3}{2}(-2-2)^2=-\frac{3}{2}(-4)^2==-\frac{3}{2}*16=-24$

Point (-2,-24)

$\displaystyle y=g(0)=-\frac{3}{2}(0-2)^2=-\frac{3}{2}(-2)^2=-\frac{3}{2}*4=-6$

Point (0,-6)

$\displaystyle y=g(2)=-\frac{3}{2}(2-2)^2=-\frac{3}{2}(0)^2=0$

Point (2,0)

$\displaystyle y=g(4)=-\frac{3}{2}(4-2)^2=-\frac{3}{2}(2)^2=-\frac{3}{2}*4=-6$

Point (4,-6)

$\displaystyle y=g(6)=-\frac{3}{2}(6-2)^2=-\frac{3}{2}(4)^2=-\frac{3}{2}*16=-24$

Point (6,-24)

The graph is shown in the image below

8 0

3 years ago

Two slits are illuminated by a 348 nm light. The angle between the zeroth-order bright band at the center of the screen and the

Andre45 [30]

Answer:0.369 m

Step-by-step explanation:

Given

Distance between slit and screen is $D=154 cm$

Wavelength $\lambda =348 nm$

Angle between zeroth order bright fringe and Fourth-order bright fringe is $\theta =13.5^{\circ}$

let distance between the slits be d

Distance of n th bright fringe From central Fringe is given by

$y_n=\frac{nD\lambda }{d}$

Also $\tan \theta =\frac{y_4}{D}$

$y_4=\tan (13.5)\cdot 1.54$

$y_4=0.24\times 1.54$

$y_4=0.369 m$

5 0

3 years ago

What is the right answer. PLEASW HELP. URGENT.

Elanso [62]

1099 square inches hope this helps

3 0

3 years ago

Solve the following system of equations.

Ronch [10]

The answer is A. I plugged it into a TI-83 calculator. If you need to know how I did that I will be happy to help

6 0

4 years ago

Read 2 more answers

Tan(a)+cot(b) simplify please.

Hitman42 [59]

Answer:

tan a + cot b

Step-by-step explanation:

It's already simplified.

There are alternate forms like

$sec(a)csc(b)cos(a-b)\\\\sec(a)csc(b)[sin(a)sin(b)+cos(a)cos(b)]\\\\\frac{sin (a)}{cos (a)} +\frac{cos(b)}{sin(b)}$

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3 years ago