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nika2105 [10]
2 years ago
11

Tuition for one year at the community college Sean would like to attend is about $8,880. Sean plans to save money each month for

the next 2 years to help pay for his first year. If his parents plan to contribute $6,000 toward his first year, what is the minimum about Sean must save each month to have enough money to pay for his first year of tuition?
A) $60
B) $80
C) $120
D) $240
Mathematics
2 answers:
blagie [28]2 years ago
8 0

Answer:

c

Step-by-step explanation:

he needs 8880.  and his parents contribute 6000.  so we subtract 6000 from the price of the tuition,  bc his parents are paying for 6000 of the 8880 and we get 2880.  there are 12 months in a year and he saves up every month for two years,  so we multiply 12 by 2 to get 24.  then we divide 2880 by 24 and you get 120.  i hope this helps

kifflom [539]2 years ago
3 0

Answer:

the answer is c

Step-by-step explanation:

<h2><u><em>The answer is C</em></u></h2>
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32 = 4+3x
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7 0
3 years ago
−9x+4y=6 9x+5y=−33 ​
blsea [12.9K]

Answer:

{x,y} = {-2,-3}

Step-by-step explanation:

System of Linear Equations entered :

  [1]    -9x + 4y = 6

  [2]    9x + 5y = -33

Graphic Representation of the Equations :

   4y - 9x = 6        5y + 9x = -33  

Solve by Substitution :

// Solve equation [2] for the variable  y  

 

 [2]    5y = -9x - 33

 [2]    y = -9x/5 - 33/5

// Plug this in for variable  y  in equation [1]

  [1]    -9x + 4•(-9x/5-33/5) = 6

  [1]    -81x/5 = 162/5

  [1]    -81x = 162

// Solve equation [1] for the variable  x  

  [1]    81x = - 162  

  [1]    x = - 2  

// By now we know this much :

   x = -2

   y = -9x/5-33/5

// Use the  x  value to solve for  y  

   y = -(9/5)(-2)-33/5 = -3

3 0
2 years ago
can someone help me to solve these two problems pls I will really appreciate I will mark you the brainly!
zavuch27 [327]

Answer:

12. 524 in³ (3 sig. fig.)   13. 2000 cm³ (3 sig. fig.)

Step-by-step explanation:

12. Volume of sphere = (4/3)πr³

= 500/3π

= 524 in³ (3 sig. fig.)

13. Volume of cylinder = πr²h

= 7²π(13)

= 637π

= 2000 cm³ (3 sig. fig.)

4 0
2 years ago
Ms. Callahan had 250 sheets of paper. She used 6 sheets of paper. She then gave each student 3 sheets of paper.
irina [24]
The answer would be D if it was 250-6-3n. it wouldnt be A or C because 9 isnt anywhere in the problem and it wouldnt be B because she used 6 peices of paper she didnt just give it to her students 
3 0
3 years ago
A scuba diving company currently charges $100per dive. On average, there are 30 customers per day. The company performed a study
Semenov [28]

A. Total Revenue (R) is equal to price per dive (P) multiplied by number of customers (C). We can write R=PC.

Per price increase is $20. So four price increase is $20*4=$80. Hence, price per dive is 100+80=$180.

Also per price increase, 2 customers are reduced from 30. For 4 price increases, 4*2=8 customers are reduced. Hence, total customers is 30-8=22.

So Total Revenue is:

R=180*22=3960


B. Each price increase is 20. So x price increase is 20x. Hence, new price per dive would be equal to the sum of 100 and 20x.

Also per price increase, customers decrease by 2. So per x price increases, the customer decrease is 2x. Hence, new number of customers is the difference of 30 and 2x.

Therefor we can write the quadratic equation for total revenue as the new price times the new number of customers.

R=(100+2x)(30-2x)=-40x^{2}+400x+3000


C. We are looking for the point (x) at which the equation modeled in part (B) gives a maximum value of revenue (y). That x value is given as x=-\frac{b}{2a}, where a is the coefficient of x^{2} and b is the coefficient of x. So we have,

x=-\frac{b}{2a}=- \frac{400}{(2)(-40)}=5

That means, the greatest revenue is achieved after 5 price increases. Each price increase was 20, so 5 price increase would be 5*20=100. So the price that gives the greatest revenue is 100+100=200.

ANSWERS:

A. $3960

B. R=-40x^{2}+400x+3000

C. $200

4 0
3 years ago
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