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irinina [24]
3 years ago
15

How do I do this? I have no idea and the assignment doesn't specify.

Mathematics
1 answer:
dalvyx [7]3 years ago
6 0
If c = 147
Then e = 180-147=33.
Reason : angle on a straight line
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An Ontario lottery has the following structure, the first person drawn from the names wins $15 000. Each subsequent person drawn
elixir [45]
  • The first four terms are : 15000, 14850, 14700, 14550
  • a = 15000 ; d = -150
  • The explicit formula is : a_{n} =  - 150n \:  + 15150

The first term of the sequence, a = 15,000

Each subsequent winner gets $150 less

Hence, the common difference, d = - $150

The first four terms :

First term, a1 = $15000

Second term, a2 = a - d = $15000 - $150 = $14850

Third term, a3 = a2 - d = $14850 - $150 = $14700

Fourth term, a4 = a3 - d = $14700 - $150 = $14550

a, for the sequence is the first term = $15000

d, for the sequence is the common $150 (difference between successive wins).

Explicit formula for the general term :

a_{n} \:  = nd \: + c

For n = 1

15000 = 1( - 150)  + c

15000 =  - 150 + c

c = 15150

Hence, the explicit formula for the nth term is :

a_{n} \:  =  - 150n \:  + 15150

Learn more : brainly.com/question/12006170

3 0
3 years ago
Shaded area=40<br> Find x <br> Width=3x<br> Length=4x<br> Not shaded area=2x
Mashutka [201]
In the process of laying out the question, you have given us important facts about the shaded area and the unshaded area. Now step back for just a second. If they're that deeply involved in the question, do you honestly expect that anybody can answer the question without seeing the picture of them ? ! ?
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a park covers a total area of 644 acres there are 482 more acres of woods than grassy areas in the park how many acres are there
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Answer:

woods are 81 acres, grass 563 acres

Step-by-step explanation:


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Elina [12.6K]
  • Answer:

<em>f(3) = 13</em>

  • Step-by-step explanation:

<em>f(x) = 2x + 7</em>

<em>replace </em><em>x</em><em> with </em><em>3</em>

<em>f(3) = 2×3 + 7</em>

<em>= 6 + 7</em>

<em>= 13</em>

8 0
3 years ago
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