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vagabundo [1.1K]
4 years ago
5

Please help md on number 4

Mathematics
1 answer:
Agata [3.3K]4 years ago
3 0
10•20=200
6•4=24
4•20=80
6•10=60

Add: 364
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Jacob is tiling his square walk with square tiles. He is able to fit 5 tiles up and 5 tiles across. If each tile has a length of
frozen [14]

Answer:

The perimeter of the kitchen wall = 60 b

Step-by-step explanation:

The number if tiles used in the length side of the square walk = 5 tiles

The length of 1 tiles  = 3 b

So, the length of 5 tiles = 5 x ( Length of 1 tile)  

= 5 x (3 b)  =  15 b

So, the length of the square walk = 1 5 b

Perimeter of SQUARE  = 4 x SIDES

⇒ Perimeter of the wall  = 4 x (Side)

                                        = 4 x (15 b)  = 60 b

Hence, the perimeter of the kitchen wall = 60 b

8 0
3 years ago
Which equation does the graph below represent?
Svetllana [295]
It represents y = -3x
3 0
2 years ago
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A restaurant sold 8 times as many salads as they sold steaks. if they sold 4 steaks, how many salads did they sell?
Mnenie [13.5K]
32. For every one salad it was 8 steaks, so if they sold 4 steaks, just multiply 4 by 8, where 8 represents the number of salads for every steak. The answer would be 32. Correct me if I'm wrong but that my answer.
7 0
3 years ago
Solve: 3 – 8x = -13 Please help
Gekata [30.6K]

Answer:

x=2

Step-by-step explanation:

7 0
3 years ago
Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th
DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0
3 years ago
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