Question

Put the following equation of a line into slope-intercept form, simplifying all

Answer 1

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

To put this into slope-intercept form, you need to isolate/get the variable "y" by itself in the equation:

8x - 6y = 6     Subtract 8x on both sides

8x - 8x - 6y = 6 - 8x

-6y = -8x + 6     Divide -6 on both sides to get "y" by itself

$\frac{-6y}{-6} =\frac{-8x+6}{-6}$

$y=\frac{-8}{-6} x+\frac{6}{-6}$

$y=\frac{4}{3}x -1$

Answer 2

Answer:

y = 4x/3 - 1

Step-by-step explanation:

The slope-intercept form is represented generally as

y = mx + c

m is the slope of the line

c is the y-intercept

Given the equation, 8x - 6y = 6

We make y subject of formula

Step 1

Add 6y to both sides of the equation

8x - 6y + 6y = 6 + 6y

8x = 6 + 6y

Step 2

Subtract 6 from both sides of the equation

8x - 6 = 6 + 6y - 6

8x - 6 = 6y

6y = 8x - 6

Step 3

Divide each term on the left hand side and right hand side of equation by the coefficient of y = 6

6y/6 = 8x/6 - 6/6

y = 4x/3 - 1

y = mx + c ~ y = 4x/3 - 1

m = 4/3

c = -1

Therefore, the slope-intercept form of the equation of the line 8x – 6y = 6 is y = 4x/3 - 1