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Dafna11 [192]
3 years ago
11

Cos(2θ) = 5 sin(θ) − 2

Mathematics
1 answer:
Solnce55 [7]3 years ago
7 0
Cos(2cos2 \alpha = 1-sin^{2}  \alpha  
. 

so...

1-sin^2\alpha = 5sin\alpha -2

sin^2\alpha + 5sin\alpha -3 = 0

Is that what you are trying to do? Find the zeros?
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