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TiliK225 [7]
4 years ago
9

Your company has 1,500 desktop computers running windows 7. you want to upgrade them to windows 8. which type of microsoft licen

se would be best-suited in this situation?
Computers and Technology
2 answers:
lakkis [162]4 years ago
5 0
Volume licensing, would be my answer.
Marina86 [1]4 years ago
4 0

Answer:

Answer to the following question is Volume Licensing.

Explanation:

The Volume licensing key is issued by an organization for the use of the client computer systems which is associated in some way with an organization.

This type of licensing is generally applied for an organization and educational institutes.

Microsoft Windows Enterprise is  activated with the volume licensing key.

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A(n) _________ Web page displays customized content in response to keyboard or mouse actions or based on information supplied di
RoseWind [281]

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5 0
2 years ago
Inside which command group will a user find the ability to configure Outlook rules used to organize a mailbox?
Sauron [17]

Answer:

You can use Outlook to perform diffrent aspects

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3 0
3 years ago
How to do assignment 5 on edhesive
s2008m [1.1K]

Answer:

//To pass in a string, and pass in a pivot string, and at that moment print in obligatory sequence, the string after pivot string till last as first string, and published beforehand the left slice of string.

import java.util.Scanner;

public class Main {

public static void main(String args[]) {

  Scanner s2 = new Scanner(System.in);

  System.out.println("Enter the parent String:");

  String f2 = s2.nextLine();

  System.out.println("Enter pivot(child string):");

  String piv1 = s2.nextLine();

  int start2 = f2.indexOf(piv1);

  int end2 = piv1.length()+start2;

  if (start2 == -1){

    System.out.println("Error: child string(Pivot) not discovered.");

    return;

}

String first2 = f2.substring(0,start2-1);

  String second2 = f2.substring(end2);

if (f2.charAt(start2-1)==' '){

System.out.println(second2 + " " + piv1 + " " + first2);

return;

}

System.out.println(second2 + piv1 + first2);

}

}

Explanation:

Please check the answer section.

6 0
3 years ago
Array Basics pls help
posledela

Answer:

import java.util.Random;

class Main {

 static int[] createRandomArray(int nrElements) {

   Random rd = new Random();

   int[] arr = new int[nrElements];

   for (int i = 0; i < arr.length; i++) {

     arr[i] = rd.nextInt(1000);

   }

   return arr;

 }

 static void printArray(int[] arr) {

   for (int i = 0; i < arr.length; i++) {

     System.out.println(arr[i]);

   }

 }

 public static void main(String[] args) {

   int[] arr = createRandomArray(5);

   printArray(arr);

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}

Explanation:

I've separated the array creation and print loop into separate class methods. They are marked as static, so you don't have to instantiate an object of this class type.

5 0
2 years ago
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