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4 years ago

What is the product?

Mathematics

1 answer:

nikitadnepr [17]4 years ago

8 0

Step-by-step explanation:

This is an example of scalar multiplication in matrices.

Just multiply the number outside with each of the number inside for this type of matrix.

That's all.

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List all of the possible rational roots.

tatuchka [14]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

section of a pipe's length and weight are in proportion. If 2.5 m of pipe weighs 10 kg, then A) 5 m of pipe weighs 30 kg. B) 5 m

motikmotik

We will proceed to resolve each case to determine the solution.

we know that

$2.5$ m of pipe weighs $10$ kg

by proportion

Find the weighs of each case

case A) $5$ m of pipe weighs $30$ kg

$\frac{10}{2.5}\frac{kg}{m}=\frac{x}{5}\frac{kg}{m}\\ \\2.5*x=5*10\\ \\x=50/2.5\\x=20\ kg$

$20\ kg\neq30\ kg$

therefore

The statement case A) is False

case B) $5$ m of pipe weighs $40$ kg

$\frac{10}{2.5}\frac{kg}{m}=\frac{x}{5}\frac{kg}{m}\\ \\2.5*x=5*10\\ \\x=50/2.5\\x=20\ kg$

$20\ kg\neq40\ kg$

therefore

The statement case B) is False

case C) $10$ m of pipe weighs $40$ kg

$\frac{10}{2.5}\frac{kg}{m}=\frac{x}{10}\frac{kg}{m}\\ \\2.5*x=10*10\\ \\x=100/2.5\\x=40\ kg$

$40\ kg=40\ kg$

therefore

The statement case C) is True

case D) $10$ m of pipe weighs $80$ kg

$\frac{10}{2.5}\frac{kg}{m}=\frac{x}{10}\frac{kg}{m}\\ \\2.5*x=10*10\\ \\x=100/2.5\\x=40\ kg$

$40\ kg\neq80\ kg$

therefore

The statement case D) is False

therefore

the answer is

$10$ m of pipe weighs $40$ kg

3 0

3 years ago

Read 2 more answers

Can somebody help me. Just number one is fine, I just want to know the concept so I can do the rest of the problems.

Keith_Richards [23]

Answer:

Q1: m = 3/4

Step-by-step explanation:

Using the formula in the attached diagram,

Consider question 1

For A(1,1) and B(5,4)

x1 = 1, y1 =1, x2= 5, y2=4

hence slope m, = (4-1) / (5-1) = 3/4 (or 0.75 if needed in decimal)

3 0

4 years ago

How could an equation in the form y=mx+b show a proportional relationship?

LenaWriter [7]

It would be proportional if the B is positive

6 0

3 years ago

Read 2 more answers

ashleigh is making 9 necklaces for cody.she has 30 feet of string to make the bows.if each bow requires 2 5/8 feet of ribbon how

pishuonlain [190]

Answer: 6.375 feet of ribbon will be left unused.

Step-by-step explanation: Given that Ashleigh is making 9 necklaces for cody.

She has 30 feet of string to make the bows and each bow requires $2\dfrac{5}{8}$ feet of ribbon.

We are to find the length of the ribbon that will be left unused.

The length of ribbon required by one bow is $2\dfrac{5}{8}~\textup{feet}.$

So, length of ribbon required by 9 bows(necklaces) is

$2\dfrac{5}{8}\times9=\dfrac{21}{8}\times9=\dfrac{189}{8}=23.625~\textup{feet}.$

Therefore, the length of the unused ribbon is

$30-23.625=6.375~\textup{ft}.$

Thus, 6.375 feet of ribbon will be left unused.

4 0

3 years ago