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kvv77 [185]
3 years ago
15

What is the greatest common factor of 91 and 11

Mathematics
2 answers:
MAVERICK [17]3 years ago
7 0
The answer to this question is 1
pantera1 [17]3 years ago
5 0

Answer:

1

Step-by-step explanation:

91:   7 13 11:  11 GCF:      

The Greates Common Factor (GCF) is:   1

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marking brainlist. please help What is the first inverse operation for the following problem? 3x+4=12
Strike441 [17]

Answer:

3x + 4 = 12 :- x = 8 / 3

Step-by-step explanation:

3x + 4 = 12

Move all terms not containing x to the right side of the equation.

Subtract 4 from both sides of the equation.

3x = 12 - 4

Subtract 4 from 12.

3x = 8

Divide each term by 3 and simplify.

Divide each term in 3x = 8 by 3.

3x / 3 = 8 / 3

Cancel the common factor of 3.

Divide x by 1.

x = 8 / 3

The result can be shown in multiple forms.

Exact Form:

x = 8 / 3

Decimal Form:

x = 2.6

Mixed Number Form:

x = 2 2/3

3 0
3 years ago
What is the equation of the given line in the point-slope form
Genrish500 [490]
First using the given two points we can find the slope (m) of the line

Slope = m =  \frac{Rise}{Run} \\  \\ 
m= \frac{4-1}{3-0} \\  \\ 
m=1

Thus the slope of given line is 1.

Using slope and a point (0,1) we can write the equation in point slope form as

y - 1= 1(x-0)
y - 1 = x

The above equation is the point-slope form of the equation.
4 0
4 years ago
The table shows the profit and loss of the after -school snack stand write each profit as a positive number and each loss a nega
kiruha [24]

Answer:

Profit

7.50

4.50

Loss

-3.50

-6.00

Step-by-step explanation:

Here, we want to write each profit as a positive number and each loss as a negative number

thus, we have that;

Profit;

7.50

4.50

Loss;

-3.50

-6.00

7 0
3 years ago
Which expression is equivalent to (x Superscript 27 Baseline y) Superscript one-third?.
marin [14]

To solve the problem we must know the basic exponential properties.

<h3>What are the basic exponent properties?</h3>

{a^m} \cdot {a^n} = a^{(m+n)}

\dfrac{a^m}{a^n} = a^{(m-n)}

\sqrt[m]{a^n} = a^{\frac{n}{m}}

(a^m)^n = a^{m\times n}

(m\times n)^a = m^a\times n^a

The expression can be written as x^9\sqrt[3]{y}.

Given to us

  • (x^{27}y)^\frac{1}{3}

(x^{27}y)^\frac{1}{3}

Using the exponential property(m\times n)^a = m^a\times n^a,

=(x^{27}y)^\frac{1}{3}\\\\=x^{\frac{27}{3}}\times y^\frac{1}{3}\\\\=x^9\times y^\frac{1}{3}

Using the exponential property \sqrt[m]{a^n} = a^{\frac{n}{m}},

=x^9\times y^\frac{1}{3}\\\\=x^9\times \sqrt[3]{y}\\\\=x^9 \sqrt[3]{y}

Hence, the expression can be written as x^9\sqrt[3]{y}.

Learn more about Exponent properties:

brainly.com/question/1807508

5 0
2 years ago
Read 2 more answers
Can someone help me do this problem and explain it to me step by step? If so I’ll mark you brainliest
Advocard [28]

Answer:

-21

28

Step-by-step explanation:

1) if r = -4

Substitute r = -4 in 3r - 9

= 3 * (-4) - 9

= -12 - 9

= -21

2) ( 4 / 7 ) * x = 16

 4 * x = 16 * 7

 x = 4 * 7

 x = 28

7 0
3 years ago
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