What your doing is your going to answer how many points or sides the shape has like a squar has 4 corners
Answer:
minimum
Step-by-step explanation:
Given a quadratic in standard form f(x) = ax² + bx + c ( a ≠ 0 )
• If a > 0 then vertex is a minimum
• If a < 0 then vertex is a maximum
f(x) = 3x² + 5x + 2 ← is in standard form
with a = 3
Since a > 0 then vertex is a minimum
Answers
Explanation
So first we’re gonna change the equation to y=Mx+b by subtracting the 8x and then dividing both sides by -4. This can be show like this
8x-4y=12
-8x. -8x
-4y=-8x+12
/-4. /-4
Y=2x-3
So now that we have the equation in Y=Mx+b. The problem still isn’t done because it’s asking us to set up an equation that’s perpendicular. Which means the slope becomes the opposite
So the slope isn’t 2 anymore but instead -1/2! So now that we know that we need to make the line go through the origin which is very easy because you can just set the y intercept to 0.
So now that the perpendicular line is
Y=-1/2x or y=-1/2x +0
I hope I explain this well!
Please mark as Brainliest
Answer: B) Infinitely many solutions; both equations are equivalent
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Work Shown:
x+y = 4 ... start with the first equation
x + (-x+4) = 4 ... replace y with (-x+4)
x-x+4 = 4
0x+4 = 4
0+4 = 4
4 = 4 ... this is a true statement regardless of what x you pick
So there are infinitely many solutions. Each solution (x,y) is of the form (x,-x+4). All solutions fall on the line y = -x+4 which is equivalent to x+y = 4. Note how we add x to both sides.
Or you could start with x+y = 4 and subtract x from both sides to get y = -x+4. Either way, we're dealing with the same equation which is why they both graph out the same line.
