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Xelga [282]
3 years ago
10

Which of the following statement is FALSE?

Mathematics
1 answer:
arlik [135]3 years ago
7 0

Answer:

The answer would be A.

Step-by-step explanation:

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What is the answer to this equation y=4x+8x for x
Juliette [100K]
Solve for x by simplifying both sides of the equation, then isolating the variable
x is equal to y/12
8 0
3 years ago
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Which expression represents the volume, in cubic units, of the shaded region of the composite figure? (14)(10)(8) – π(2.52)(8) (
julia-pushkina [17]

Answer:

A. 1/2(14)(10)(8) – π(2.5^2)(8)

Step-by-step explanation:

I took the test and this was the correct answer. Hope this helped!

7 0
2 years ago
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If you had 1052 toothpicks and were asked to group them in powers of 6, how many groups of each power of 6 would you have? Put t
sukhopar [10]

1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

The number 1052, written as a base 6 number is 4512

Given: 1052 toothpicks

To do: The objective is to group the toothpicks in powers of 6 and to write the number 1052 as a base 6 number

First we note that, 6^{0}=1,6^{1}=6,6^{2}=36,6^{3}=216,6^{4}=1296

This implies that 6^{4} exceeds 1052 and thus the highest power of 6 that the toothpicks can be grouped into is 3.

Now, 6^{3}=216 and 216\times 5=1080, 216\times 4=864. This implies that 216\times 5 exceeds 1052 and thus there can be at most 4 groups of 6^{3}.

Then,

1052-4\times6^{3}

1052-4\times216

1052-864

188

So, after grouping the toothpicks into 4 groups of third power of 6, there are 188 toothpicks remaining.

Now, 6^{2}=36 and 36\times 5=180, 36\times 6=216. This implies that 36\times 6 exceeds 188 and thus there can be at most 5 groups of 6^{2}.

Then,

188-5\times6^{2}

188-5\times36

188-180

8

So, after grouping the remaining toothpicks into 5 groups of second power of 6, there are 8 toothpicks remaining.

Now, 6^{1}=6 and 6\times 1=6, 6\times 2=12. This implies that 6\times 2 exceeds 8 and thus there can be at most 1 group of 6^{1}.

Then,

8-1\times6^{1}

8-1\times6

8-6

2

So, after grouping the remaining toothpicks into 1 group of first power of 6, there are 2 toothpicks remaining.

Now, 6^{0}=1 and 1\times 2=2. This implies that the remaining toothpicks can be exactly grouped into 2 groups of zeroth power of 6.

This concludes the grouping.

Thus, it was obtained that 1052 toothpicks can be grouped into 4 groups of third power of 6 (6^{3}), 5 groups of second power of 6 (6^{2}), 1 group of first power of 6 (6^{1}) and 2 groups of zeroth power of 6 (6^{0}).

Then,

1052=4\times6^{3}+5\times6^{2}+1\times6^{1}+2\times6^{0}

So, the number 1052, written as a base 6 number is 4512.

Learn more about change of base of numbers here:

brainly.com/question/14291917

6 0
2 years ago
This year, Arvin and Mariah were in charge of making orange juice for campers. They planned to make the juice by mixing water an
zavuch27 [327]

Answer:

Mix A is the most orangey, Mix C is the least orangey

Step-by-step explanation:

Mix A largest proportion of concentrate to water

Mix C is the smallest proportion of concentrate to water

8 0
3 years ago
9 is 150% of what number​
damaskus [11]

Answer:

13.5

Step-by-step explanation:

150% × 9 =

(150 ÷ 100) × 9 =

(150 × 9) ÷ 100 =

1,350 ÷ 100 =

13.5

My proof :

If 150% × 9 = 13.5 =>

Divide 13.5 by 9... ... And see if we get as a result: 150%.

4 0
2 years ago
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