Question

Points A and B have the coordinates shown below.

Answer 1

Answer:

Distance AB is 18.79 units

Step-by-step explanation:

Given two points with coordinates as:

A= (-4,7)

B= (-12, -10)

To find:

Distance AB = ?

Solution:

To find the distance between two points with given coordinates, we can use Distance formula.

Distance formula  is given as:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

where $(x_1, y_1)$ and $(x_2, y_2)$ are the two coordinates whose distance is to be find out.

$x_1 = -4\\y_1 = 7\\x_2 = -12\\y_2 = -10$

$AB = \sqrt{(-12-(-4))^2+(-10-7)^2}\\\Rightarrow AB = \sqrt{(-8)^2+(-17)^2}\\\Rightarrow AB = \sqrt{64+289}\\\Rightarrow AB = \sqrt{353}\\\Rightarrow \bold{AB = 18.79\ units }$

Distance AB is 18.79 units

Answer 2

Answer:

AB = 18.8 units

Step-by-step explanation:

If there are two points (x1,y1) and (x2,y2) on the coordinate plane.

distance between those two points = $\sqrt{(x1-x2)^{2} + (y1-y2)^{2} }$

given points are

A= (-4,7)

B= (-12, -10)

$AB = \sqrt{(-4 -(-12))^{2} + (7-(-10))^{2} }\\AB = \sqrt{(-4 +12)^{2} + (7+10)^{2} }\\AB = \sqrt{(8)^{2} + (17)^{2} }\\AB = \sqrt{64 + 289 }\\AB = \sqrt{353 }\\AB = 18.79$

Thus, length of AB is 18.79 units

since, value of hudredth of unit is 9 which is greater than 9 then rounding the value to nearest tenth of unit we increase the value at tenth of unit place by that is 7 becomes 8

length of AB  to the nearest tenth of a unit is 18.9 units