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Kruka [31]
3 years ago
9

Rabbits can breed for the first time at the age of three months. They have a gestation period of about 31 days, and there can be

anywhere from four to 12 young in each litter. What would be the most likely long-term consequence if a breeding pair of rabbits was released into an ecosystem with no predators large enough to eat a rabbit?
Biology
2 answers:
lara31 [8.8K]3 years ago
7 0

Answer:

They would most likely overpopulate. That sounds like a good thing, but if that happens they would exhaust their food supply way to quickly and they would starve to death. This is why they need a predator, to balance the ecosystem.....The rabbit population would grow quickly until all the edible vegetation was gone and then the rabbit population would crash.

Explanation:

77julia77 [94]3 years ago
5 0

Answer:

needs points apologies

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Shalnov [3]

Answer:

The phenotypic variance= 2113

The eenvironmenal variance= 644

The genetic variance= 1469

The broad-sense heritability = 0.695

Explanation:

To determine the phenotypic variance, we need to know the calculate the environmental variance and the genetic variance first;

because Phenotypic variance = V(p) such that;

V(p) = V(e) + V(g)                  

where V(e)  =  environmental variance and V(g)   =  genetic variance

Therefore, Environmental variance can be defined as a portion of phenotypic variance due to differences in the environments to which the individuals in a population have been exposed. The total amount of variance observed is dependent on the genetic component, determined by the variation that is inherited.

This implies that V(e)= initial variance which was there in the parents ( i.e  Variance of inbred line 1 = 311  and Variance of inbred line 2 = 333 )

V(e) = (311 + 333) = 644

Genetic Variance simply refer to the variance that occurs or preferrably , that is observed after inbreeding (i.e Variance of F1 = 316  and Variance of F2 = 1153)

V(g)  = (316 + 1153) = 1469

Now, back to phenotypic variance = V(e) + V(g)

substituting the parameters we have;  1469 + 644 = 2113

Broad-sense heritability can be calculated as the ratio of total genetic variance to total phenotypic variance.

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