Consider the system.

Priya and Han both factored the number 80. Priya says they should both get the same answer even if they started with different f

meriva

Answer:

Priya is right.

Step-by-step explanation:

The factors of 80 is 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

The factor pairs of 80 are

1 x 80, 2 x 40, 4 x 20, 5 x 16 and 8 x 10

If Priya picks 2 x 40, then it's prime factorisation will be, 2 x 2 x 2 x 2 x 5 = 2⁴ x 5.

If Han picks, 5 x 16 = 5 x 2 x 2 x 2 x 2 = 5 x 2⁴ = 2⁴ x 5. This is the same.

Therefore, Priya is correct, because the factors of 80 are always the same, therefore which ever you start with, you'd always get the same answer.

4 0

2 years ago

What is the probability that a random person who tests positive for a certain blood disease actually has the disease, if we know

xeze [42]

Answer:

Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

True positive (test is + and the patient is sick) ⇒ P(+ ∩ S)

False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

True negative (test is - and the patient is healthy) ⇒ P(- ∩ H)

False-negative (test is - but the patient is sick) ⇒ P(- ∩ S)

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true positive rate).

⇒ P(+/S) = P(+ ∩ S)

P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly healthy (true negative rate)

⇒ P(-/H) = P(- ∩ H)

P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= P(+ ∩ S)

P(+)

The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) = P(+ ∩ S)

P(S)

P(+/S)* P(S) = P(+ ∩ S)

P(+ ∩ S) = 0.95*0.01= 0.0095

The second step is to calculate the probability of the test being positive:

P(+)= P(+ ∩ S) + P(+ ∩ H)

Now we know that 1% of the population has the blood sickness, wich means that 99% of the population doesn't have it, symbolically: P(H)= 0.99

Then you can clear the value of P(+ ∩ H):

P(+/H) = P(+ ∩ H)

P(H)

P(+/H)*P(H) = P(+ ∩ H)

P(+ ∩ H) = 0.02*0.99= 0.0198

Next you can calculate P(+):

P(+)= P(+ ∩ S) + P(+ ∩ H)= 0.0095 + 0.0198= 0.0293

Now you can calculate the asked probability:

P(S/+)= P(+ ∩ S) = 0.0095 = 0.32

P(+) 0.0293

I hope it helps!

6 0

2 years ago

Workout the median 6266 6626 6622 6226 6662 6222 7466

sasho [114]

Answer:

Step-by-step explanation:

the median would be 2,2 just the middle number/numbers if it has 1 # thats the median if it has 2 thats still the median

7 0

3 years ago

Read 2 more answers

2cosx-3=0 cách giải như thế nào

Masteriza [31]

Answer:

Solution does not exist.

Step-by-step explanation:

2cosx-3=0

2cosx=3

cosx=3/2

Solution does not exist.

7 0

3 years ago

Someone plzzzz convert 3.005342 for meeeeee.

mars1129 [50]

Answer:

Please mark my other question brainliest and I'll answer this.

Step-by-step explanation:

7 0

3 years ago