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4 years ago

M/7 + 1 = 6 ? What is it equal too

Mathematics

1 answer:

jasenka [17]4 years ago

5 0

Answer: M= 35

The correct answer to m/7 + 1 = 6 is M = 35

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80 is what percent of 10

Step2247 [10]

80/10=8
8=800%

80 is 800% of 10

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3 years ago

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What is the value of the missing angle

blondinia [14]

Answer:

30°

Step-by-step explanation:

Since a straight line is 180°, you have to subtract 180 by 150. This will give you 30

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3 years ago

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1. Angle 3 and Angle 6 are examples of which type of angle pair?

mars1129 [50]

Your answer is:Alternate Interior Angles

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3 years ago

What condition renders this true, where S and T are sets?

daser333 [38]

Answer:

There are no sets S, T for which

$S \cup T^c=S^c\cap T$

holds

Step-by-step explanation:

Let the set A be

$A=S\cup T^c$

By de De Morgan's Law

$A^c=S^c\cap ((T)^c)^c$

But

$((T)^c)^c=T$

$A^c=S^c\cap T$

We conclude that

$S \cup T^c=S^c\cap T\Rightarrow A=A^c$

which is a contradiction because no set is equal to its complement.

3 0

3 years ago

ABCD- parallelogram, If the perimeter of Triangle CPQ is 15cm, Find the perimeter of triangle BAQ. Find the perimeter of triangl

melamori03 [73]

Answer:

The answer is below

Step-by-step explanation:

A parallelogram is a quadrilateral (has 4 sides and 4 angle) with two pair of parallel and opposite sides. Opposite sides of a parallelogram are parallel and equal.

Given parallelogram ABCD:

AB = CD = 18 cm; BC = AD = 8 cm

∠P = ∠P, ∠PDA = ∠PCQ (corresponding angles are equal).

Hence ΔPCQ and ΔPDA are similar by angle-angle similarity theorem. For similar triangles, the ratio of their corresponding sides equal. Therefore:

$\frac{CD}{PC}= \frac{AD}{CQ}\\\\\frac{18}{6}=\frac{8}{x} \\\\x=\frac{6*8}{18}=\frac{8}{3}\ cm$

Perimeter of CPQ = CP + CQ + PQ

15 = 6 + 8/3 + PQ

PQ = 15 - (6 + 8/3)

PQ = 6.33

∠CQP = ∠AQB (vertical angles), ∠QCP = ∠QBA (alternate angles are equal).

Hence ΔCPQ and ΔABQ are similar by angle-angle similarity theorem

$\frac{AQ}{QP}=\frac{AB}{CP} \\\\\frac{AQ}{6.33} =\frac{18}{6} \\\\AQ=\frac{18}{6}*6.33\\\\AQ = 19$

$\frac{BQ}{CQ}=\frac{AB}{CP} \\\\\frac{BQ}{8/3} =\frac{18}{6} \\\\BQ=\frac{18}{6}*\frac{8}{3} \\\\BQ =8$

Perimeter of BAQ = AB + BQ + AQ = 18 + 8 + 19 = 45cm

PA = AQ + PQ = 19 + 6.33 = 25.33

PD = CD + DP = 18 + 6 = 24

Perimeter of PDA = PA + PD + AD = 24 + 25.33 + 8 = 57.33 cm

7 0

3 years ago