7x the third power
<span>=<span>7*<span>x3</span></span></span><span>=<span>7*<span>(<span><span>x*x</span>*x</span>)</span></span></span><span>=<span>7<span>x<span>3
</span></span></span></span>7x the tenth power
<span>=<span>7*<span>x10</span></span></span><span>=<span>7*<span>(<span><span><span><span><span><span><span><span><span>x*x</span>*x</span>*x</span>*x</span>*x</span>*x</span>*x</span>*x</span>*x</span>)</span></span></span><span>=<span>7<span>x<span>10</span></span></span></span>
Your question is:
![\frac{8u}{u^2-18u+81} -\frac{72}{u^2-18u+81}](https://tex.z-dn.net/?f=%5Cfrac%7B8u%7D%7Bu%5E2-18u%2B81%7D%20-%5Cfrac%7B72%7D%7Bu%5E2-18u%2B81%7D)
Then, the above formula equate:
![\frac{8u-72}{u^2-18u+81}](https://tex.z-dn.net/?f=%5Cfrac%7B8u-72%7D%7Bu%5E2-18u%2B81%7D)
Factor out 8 from the numerator we get:
![\frac{u-9}{u^2-18u+81}](https://tex.z-dn.net/?f=%5Cfrac%7Bu-9%7D%7Bu%5E2-18u%2B81%7D)
Factorization of the denominator:
![\frac{u-9}{(u-9)^2}](https://tex.z-dn.net/?f=%5Cfrac%7Bu-9%7D%7B%28u-9%29%5E2%7D)
Simplifying the numerator and the denominator by (u-9) we get:
Median is the middle number in a sorted list of numbers so in your question the number in the middle is 4 so the median is 4.
Answer:
![\frac{24}{25}](https://tex.z-dn.net/?f=%5Cfrac%7B24%7D%7B25%7D)
Step-by-step explanation:
Given
cosA =
= ![\frac{adjacent}{hypotenuse}](https://tex.z-dn.net/?f=%5Cfrac%7Badjacent%7D%7Bhypotenuse%7D)
Then the opposite side using Pythagorean triple is 4, thus
sinA = ![\frac{4}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B5%7D)
Using the trigonometric identity
sin2A = 2 sinAcosA, then
sin2A = 2 ×
× ![\frac{3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B5%7D)
=
= ![\frac{24}{25}](https://tex.z-dn.net/?f=%5Cfrac%7B24%7D%7B25%7D)