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Molodets [167]
2 years ago
10

And I'm stuck again ahahah.

Mathematics
2 answers:
Mariana [72]2 years ago
7 0

Answer:

Hewo can i has fortnight

Step-by-step explanation:

IceJOKER [234]2 years ago
6 0
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Angle XBC = 55 degrees because corresponding angles are equal

b) We already know angle XBC

Angle XCB = Angle XBC because isosceles base angles are equal

Therefore, angle XCB = 55 degrees

Angles in a triangle equal 180 degrees

180 - (55 + 55) = 70

Angle BXC = 70 degrees

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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-4/3 divided by (-12)
marissa [1.9K]

Answer:

0.11111111111

Step-by-step explanation:

i hope this is right! if not im sorry!

7 0
3 years ago
Read 2 more answers
What is the length of AB?<br> O A. 9<br> O B. 18<br> O C. 48<br> D. 6
insens350 [35]
<h3>Answer:  A.  9</h3>

=====================================================

Explanation:

Draw in the segments AO and OC.

Triangle ABO is congruent to triangle CBO. We can prove this through the use of the HL theorem. HL stands for hypotenuse leg.

Since the triangles are congruent, this means the corresponding pieces AB and BC are the same length.

Then we can say:

AB+BC = AC .... segment addition postulate

AB+AB = AC .... plug in BC = AB

2*AB = AC

2*AB = 18

AB = 18/2 .... divide both sides by 2

AB = 9

In short, the chord AC is bisected by the perpendicular radius drawn in the diagram. So all we do is cut AC = 18 in half to get AB = 9.

6 0
2 years ago
Read 2 more answers
If the point (x, –1) is on the unit circle, what is the value of x?
aleksklad [387]
The value of x will be 0
6 0
2 years ago
Two fair coins are flipped. Given that at least one coin lands on a head, calculate the probability of one head and one tail. Wr
Greeley [361]

The probability of one head and one tail is 2/3.

<u>Step-by-step explanation</u>:

  • The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
  • Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities
  • Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities

To calculate the probability of one head and one tail,

Probability = required events / Total events

Probability = 2/3

8 0
3 years ago
Answer this for me please
dybincka [34]

Answer:

-3

Step-by-step explanation:

You cant count the spaces up (9) and over (-3) between the two points and do up/over so it would be 9/-3 and simplified that is -3/1 or 3

6 0
2 years ago
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